SELECT  
SUM(VW_LSXHMX.SL*ISNULL(VW_LSXHMX.DJ_3,0) )  AS CBJE 
FROM [color=#FF0000](
select DJXZ,DJMC,DJBH,RQ,YSRQ,JZRQ,DM1,DM2,QDDM,YGDM,YS,JZ,JS,ZDR,YSR,JZR,JSR,BZ,SPDM,
SUM(SL) AS SL,SUM(SL*CKJ) AS BZJE,sum(JE) AS JE,sum(BYZD9) AS BYZD9,LX from VW_LSXHMX_A  GROUP 
BY DJXZ,DJMC,DJBH,RQ,YSRQ,JZRQ,DM1,DM2,QDDM,YGDM,YS,JZ,JS,ZDR,YSR,JZR,JSR,BZ,SPDM,LX )[/color] VW_LSXHMX left outer join (select distinct LSDJBH,RQ,SPDM,DM1,sum(SL) as SL,sum(JE) as 
JE,SUM(JE_2) AS JE_2 from VW_SDJSD where VW_SDJSD.JZ='1' GROUP BY  LSDJBH,RQ,SPDM,DM1) 
VW_SDJSD  on  VW_LSXHMX.DJBH=VW_SDJSD.LSDJBH AND VW_LSXHMX.SPDM=VW_SDJSD.SPDM AND
 VW_LSXHMX.DM1=VW_SDJSD.DM1,SHANGPIN,KEHU,DANWEI,FJSX1,FJSX2,FJSX3,FJSX4  WHERE 
VW_LSXHMX.SPDM=SHANGPIN.SPDM AND VW_LSXHMX.DM1=KEHU.KHDM AND SHANGPIN.DWMC = 
DANWEI.DWDM  AND SHANGPIN.FJSX1=FJSX1.SXDM AND SHANGPIN.FJSX2=FJSX2.SXDM AND 
SHANGPIN.FJSX3=FJSX3.SXDM AND SHANGPIN.FJSX4=FJSX4.SXDM  [color=#FFFF00]AND ((VW_LSXHMX.LX = '0') ) [/color]GROUP BY KEHU.KHDM,KEHU.KHMC,KEHU.BYZD8

select DJXZ,DJMC,DJBH,RQ,YSRQ,JZRQ,DM1,DM2,QDDM,YGDM,YS,JZ,JS,ZDR,YSR,JZR,JSR,BZ,SPDM,
SUM(SL) AS SL,SUM(SL*CKJ) AS BZJE,sum(JE) AS JE,sum(BYZD9) AS BYZD9,LX 
from VW_LSXHMX_A 
GROUP BY DJXZ,DJMC,DJBH,RQ,YSRQ,JZRQ,DM1,DM2,QDDM,YGDM,YS,JZ,JS,ZDR,YSR,JZR,JSR,BZ,SPDM,LX

------解决方案--------------------
探讨

那我更不明白了。我查询的是VW_LSXHMX.DJ_3
和VW_LSXHMX_A.DJ_3有关系？


------解决方案--------------------
顶AcHerat,其实问题很简单不诡异.