日期:2014-05-18  浏览次数:20549 次

再求sql,最近发春,一直会想起好多sql要写
某表tb,一列a
a
str1
str2
str3
str4
str5
str6
str7
str8
....
想把每两行的字符串连接起来,如
a
str1str2
str3str4
str5str6
......

再求高手





------解决方案--------------------
--sql 2000用函数解决:
SQL code
create table tb(a varchar(10))
insert into tb values('str1')
insert into tb values('str2')
insert into tb values('str3')
insert into tb values('str4')
insert into tb values('str5')
insert into tb values('str6')
insert into tb values('str7')
insert into tb values('str8')
go

--创建函数解决:
create function dbo.f_str(@px int) returns varchar(1000)
as
begin
  declare @str varchar(1000)
  select @str = isnull(@str , '') + cast(a as varchar) from (select t.* , px = (((select count(1) from tb where a < t.a) + 1) - 1)/2 from tb t) m where px = @px
  return @str
end
go


--调用函数
select dbo.f_str(px) a from
(
  select t.* , px = (((select count(1) from tb where a < t.a) + 1) - 1)/2 from tb t
) m
group by px

drop function dbo.f_str

drop table tb

/*

a                     
----------------------
str1str2
str3str4
str5str6
str7str8

(所影响的行数为 4 行)
*/

------解决方案--------------------
探讨

--sql 2000用函数解决:
SQL code
create table tb(a varchar(10))
insert into tb values('str1')
insert into tb values('str2')
insert into tb values('str3')
insert into tb values('str4')
insert into tb value……

------解决方案--------------------
--sql 2005
SQL code
create table tb(a varchar(10))
insert into tb values('str1')
insert into tb values('str2')
insert into tb values('str3')
insert into tb values('str4')
insert into tb values('str5')
insert into tb values('str6')
insert into tb values('str7')
insert into tb values('str8')
go

select a = replace(stuff((select ',' + a from 
(
  select t.* , px = (row_number() over(order by a) - 1)/2 from tb t
) m where m.px = n.px for xml path('')) , 1 , 1 , ''),',','')
from 
(
  select t.* , px = (row_number() over(order by a) - 1)/2 from tb t
) n
group by px

drop table tb

/*
a
------------
str1str2
str3str4
str5str6
str7str8

(4 行受影响)
*/

------解决方案--------------------
SQL code
--> --> (Roy)生成測試數據
 
if not object_id('Tempdb..#a') is null
    drop table #a
Go
Create table #a([Col] nvarchar(4))
Insert #a
select N'str1' union all
select N'str2' union all
select N'str3' union all
select N'str4' union all
select N'str5' union all
select N'str6' union all
select N'str7' union all
select N'str8'
Go
;with a
as
(
Select *,ROW_NUMBER()over(order by getdate()) as row from #a
)
select 
    a.[Col]+ISNULL(b.[Col],'') as Str1
from a
    left join a as b on a.row=b.row-1
where a.row%2=1

/*
str1str2
str3str4
str5str6
str7str8
*/