日期:2014-05-18  浏览次数:20600 次

把表由一行 变 二行
有一表:table1
code name total
0001 品名1 10
0001 品名1 20
0002 品名2 10
0002 品名2 20
0001 品名1 30

想把上面的表变两行,按code分组,同一组可分放两行,不同组的换新行。
如下表结果.(生成另一新表table2)
code name total code name total
0001 品名1 10 0001 品名1 20
0001 品名1 30
0002 品名2 10 0002 品名2 20

请教!

------解决方案--------------------
SQL code
--> --> (Roy)生成測試數據
 
if not object_id('Tempdb..#T') is null
    drop table #T
Go
Create table #T([code] nvarchar(4),[name] nvarchar(3),[total] int)
Insert #T
select N'0001',N'品名1',10 union all
select N'0001',N'品名1',20 union all
select N'0002',N'品名2',10 union all
select N'0002',N'品名2',20 union all
select N'0001',N'品名1',30
Go
with a
as
(
select *
from 
(
select [code],[name],[total],ROW_NUMBER()over(partition by [code] order by row) as Row,ROW_NUMBER()over(partition by [code] order by row) -Row as grp
from (Select *,row=ROW_NUMBER()over(order by (select 1)) from #T)t
)t2
)
select a.code,a.name,a.total,b.code,b.name,b.total
from a left join a as b on a.grp=b.grp and a.code=b.code and a.Row=b.Row-1
where a.Row%2=1

/*
code    name    total    code    name    total
0001    品名1    10    0001    品名1    20
0001    品名1    30    NULL    NULL    NULL
0002    品名2    10    0002    品名2    20
*/

------解决方案--------------------
SQL code
---------------------------------
--  Author: HEROWANG(让你望见影子的墙)
--  Date  : 2012-04-20 08:15:47
--  blog  : blog.csdn.net/herowang
---------------------------------
 
IF OBJECT_ID('[tb]') IS NOT NULL 
    DROP TABLE [tb]
go
CREATE TABLE [tb] (code VARCHAR(4),name VARCHAR(5),total INT)
INSERT INTO [tb]
SELECT '0001','品名1',10 UNION ALL
SELECT '0001','品名1',20 UNION ALL
SELECT '0002','品名2',10 UNION ALL
SELECT '0002','品名2',20 UNION ALL
SELECT '0001','品名1',30

select * from [tb]

go
with cte as
(select row=row_number() over(partition by code order by getdate() ),* from tb)
select * 
from cte s left join cte t on s.code=t.code and s.row=t.row-1
where s.row %2=1 

1    0001    品名1    10    2    0001    品名1    20
3    0001    品名1    30    NULL    NULL    NULL    NULL
1    0002    品名2    10    2    0002    品名2    20

------解决方案--------------------
SQL code
--2000 可以用这方法,获得序列值;剩下的思路同楼上各位

row= (select Count(1) +1 from tb)

------解决方案--------------------
SQL code

IF OBJECT_ID('[tb]') IS NOT NULL 
    DROP TABLE [tb]
go
CREATE TABLE [tb] (code VARCHAR(4),name VARCHAR(5),total INT)
INSERT INTO [tb]
SELECT '0001','品名1',10 UNION ALL
SELECT '0001','品名1',20 UNION ALL
SELECT '0002','品名2',10 UNION ALL
SELECT '0002','品名2',20 UNION ALL
SELECT '0001','品名1',30
go
alter table tb add id int identity
go
select s.code,s.name,s.total,t.code,t.name,t.total 
from (
select row=(select COUNT(1) from tb b 
where a.code=b.code and b.id<=a.id),* from tb a
) s left join (select row=(select COUNT(1) from tb b 
where a.code=b.code and b.id<=a.id),* from tb a)t  on s.code=t.code and s.row=t.row-1
where s.row %2=1 order by s.code
/*
code    name    total    code    name    total
0001    品名1    10    0001    品名1    20
0001    品名1    30    NULL    NULL    NULL
0002    品名2    10    0002    品名2    20
*/
go
alter table tb drop column id
drop table tb

--接楼上测试数据用了。

--TravyLee小号