日期:2014-05-18 浏览次数:21055 次
编写一个存储过程,包含一个输入参数, 指定阶乘最大值,包含一个输出参数,返回阶乘的值。 create proc pro @n int,@sum int output as declare @index int set @index=1 set @sum=1 while(@index<=@n) begin set @sum=@sum*@index set @index=@index+1 end declare @sum int exec pro 10,@sum output select @sum as 结果为 4、编写一个存储过程,统计两个输入参数间能被整除 的整数个数及这些整数的和,两个输入参数,两个输 出参数。 create proc pron @n int,@m int,@sum int output,@total int output as set @sum=0 set @total=0 while (@n<=@m) begin if @n%13=0 begin set @sum=@sum+@n set @total=@total+1 set @n=@n+1 end else set @n=@n+1 end declare @sum int,@total int exec pron 5,1000,@sum output,@total output select @sum as 总和,@total as 总个数 参考
------解决方案--------------------
学生挂科率,和各个科目挂科率。表达式能贴出来。
------解决方案--------------------
--如果是查询
--学生考试挂科率
select m.id , m.student_name , cast(isnull(n.cnt, 0)*100.0 / m.cnt as decimal(18,2)) [挂科率] from
(select id , student_name , count(1) cnt from test_student group by id , student_name ) m
left join
(select id , student_name , count(1) cnt from test_student where core < 60 group by id , student_name ) n
on m.id = n.id
--各个科目的挂科率
select m.course_name , cast(isnull(n.cnt, 0)*100.0 / m.cnt as decimal(18,2)) [挂科率] from
(select course_name , count(1) cnt from test_student group by course_name) m
left join
(select course_name , count(1) cnt from test_student where core < 60 group by course_name) n
on m.course_name = n.course_name
--如果是要存储过程
--学生考试挂科率
create procedure my_proc1 as
begin
select m.id , m.student_name , cast(isnull(n.cnt, 0)*100.0 / m.cnt as decimal(18,2)) [挂科率] from
(select id , student_name , count(1) cnt from test_student group by id , student_name ) m
left join
(select id , student_name , count(1) cnt from test_student where core < 60 group by id , student_name ) n
on m.id = n.id
end
--各个科目的挂科率
crete procedure my_proc2 as
begin
select m.course_name , cast(isnull(n.cnt, 0)*100.0 / m.cnt as decimal(18,2)) [挂科率] from
(select course_name , count(1) cnt from test_student group by course_name) m
left join
(select course_name , count(1) cnt from test_student where core < 60 group by course_name) n
on m.course_name = n.course_name
end