日期:2014-05-18 浏览次数:20500 次
create table #A(mainID int,subID int) create table #B(subID int,f1 int) insert into #A select 1,1 union all select 1 ,2union all select 1 ,3union all select 2 ,4union all select 2 ,5union all select 2, 6 insert into #B select 1, 1 union all select 1 ,2union all select 2, 6union all select 3, 5union all select 3, 2union all select 3, 7 select mainid,SUM(m.f1) from #A join (select subid,SUM(f1) as f1 from #b group by subid) m on #A.subid=m.subid group by mainid
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select mainID,SUM(fi) from 表一 t1,表二 t2 where t1.subID=t2.subID group by mainID
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select mainid,SUM(f1) from #A join #B on #A.subID=#B.subID group by mainID
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create table t1(mainID int,subID int) insert into t1 values(1 ,1) insert into t1 values(1 ,2) insert into t1 values(1 ,3) insert into t1 values(2 ,4) insert into t1 values(2 ,5) insert into t1 values(2 ,6) create table t2(subID int,f1 int) insert into t2 values(1 ,1) insert into t2 values(1 ,2) insert into t2 values(2 ,6) insert into t2 values(3 ,5) insert into t2 values(3 ,2) insert into t2 values(3 ,7) --如果不存在的不显示 select m.mainID , sum(n.f1) f1 from t1 m, t2 n where m.subID = n.subID group by m.mainID /* mainID f1 ----------- ----------- 1 23 (所影响的行数为 1 行) */ --如果不存在的也要显示,且显示为0 select m.mainID , isnull(sum(n.f1),0) f1 from t1 m left join t2 n on m.subID = n.subID group by m.mainID /* mainID f1 ----------- ----------- 1 23 2 0 (所影响的行数为 2 行) */ drop table t1 , t2
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求记录条数 create table #A(mainID int,subID int) create table #B(subID int,f1 int) insert into #A select 1,1 union all select 1 ,2union all select 1 ,3union all select 2 ,4union all select 2 ,5union all select 2, 6 insert into #B select 1, 1 union all select 1 ,2union all select 2, 6union all select 3, 5union all select 3, 2union all select 3, 7 select mainid,count(f1) from #A left join #B on #A.subID=#B.subID group by mainID 结果显示为: mainid num 1 6 2 0