日期:2014-05-18 浏览次数:20568 次
--> 测试数据:[t1] if object_id('[t1]') is not null drop table [t1] create table [t1]([id] int,[ord_id] int) insert [t1] select 1,10 union all select 2,10 union all select 3,20 union all select 4,20 union all select 5,20 select id,(select min(id) from t1 a where a.[ord_id]=b.[ord_id]) as [newid] ,[ord_id] from t1 b group by [ord_id],id /* id newid ord_id 1 1 10 2 1 10 3 3 20 4 3 20 5 3 20 */