日期:2014-05-18 浏览次数:20701 次
select right('http://xxx.xxxxx.com.cn/SZ374.html',charindex('/',REVERSE('http://xxx.xxxxx.com.cn/SZ374.html'))-1)
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declare @a varchar(300) set @a='http://xxx.xxxxx.com.cn/SZ374.html' select right(@a,charindex('/',REVERSE(@a))-1) go declare @a varchar(300) set @a='http://xxx.xxxxx.rytryrtcom.cn/SZtryrt374.html' select right(@a,charindex('/',REVERSE(@a))-1)
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declare @table table (deptcode varchar(34)) insert into @table select 'http://xxx.xxxxx.com.cn/SZ374.html' union all select 'http://xxx.xxxxx.com.cn/SZ373.html' union all select 'http://xxx.xxxxx.com.cn/abd44.html' union all select 'http://xxx.xxxxx.com.cn/tsss.html' SELECT SUBSTRING(deptcode,LEN(deptcode)-CHARINDEX('/',REVERSE(deptcode))+2, CHARINDEX('/',REVERSE(deptcode))-CHARINDEX('.',REVERSE(deptcode))-1) AS newcol from @table /* newcol ---------------------------------- SZ374 SZ373 abd44 tsss */
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mysql> use c1 Database changed mysql> select * from a; +----+-------------------------------------------------+ | id | Talent | +----+-------------------------------------------------+ | 1 | http://xxx.xxxxx.com.cn/SZ374.html | | 2 | http://xxx.xxxxx.com.cn/SZ374121212.html | | 3 | http://xxx.xxx.com.cn/SZ3741212121312.html | | 4 | http://xxx.xxxxxxxx.com.cn/SZ3741212121312.html | +----+-------------------------------------------------+ 4 rows in set (0.00 sec) mysql> select Mid(talent,instr(talent,'com.cn/')+7,instr(talent,'.html')-instr(t alent,'com.cn/')-7) from a; +------------------------------------------- --------+ | Mid(talent,instr(talent,'com.cn/')+7,instr(talent,'.html')-instr(talent,'com.c n/')-7) | +------------------------------------------- --------+ | SZ374 | | SZ374121212 | | SZ3741212121312 | | SZ3741212121312 | +------------------------------------------- --------+ 4 rows in set (0.00 sec) mysql>
------解决方案--------------------
declare @a varchar(300)
set @a='http://xxx.xxxxx.rytryrtcom.cn/SZ374.html'
select left(right(@a,charindex('/',REVERSE(@a))-1),charindex('.',right(@a,charindex('/',REVERSE(@a))-1))-1)
------解决方案--------------------
select parsename(right('http://xxx.xxxxx.com.cn/SZ374.html',PATINDEX ('%/%', REVERSE('http://xxx.xxxxx.com.cn/SZ374.html'))-1),2)
------解决方案--------------------
select parsename(right('http://xxx.xxxxx.com.cn/SZ374.html',charindex ('/', REVERSE('http://xxx.xxxxx.com.cn/SZ374.html'))-1),2)
------解决方案--------------------
同学,楼上的都是标准答案啊:
SELECT newrow = SUBSTRING(deptcode,LEN(deptcode)-CHARINDEX('/',REVERSE(deptcode))+2, CHARINDEX('/',REVERSE(deptcode))-CHARINDEX('.',REVERSE(deptcode))-1) FROM table_name