[ID] [int] IDENTITY(1,1) NOT NULL,
    [iNO] [nvarchar](20) NOT NULL,
    [NonMemo] [ntext] NULL,

-- Title: 在SQL中分类合并数据行
-- Author: dobear        Mail(MSN): dobear_0922@hotmail.com
-- Environment: Vista + SQL2005
-- Date: 2008-04-22
-- =============================================================================

--1. 创建表，添加测试数据
CREATE TABLE tb(id int, [value] varchar(10))
INSERT tb SELECT 1, 'aa'
UNION ALL SELECT 1, 'bb'
UNION ALL SELECT 2, 'aaa'
UNION ALL SELECT 2, 'bbb'
UNION ALL SELECT 2, 'ccc'

--SELECT * FROM tb
/**//*
id          value
----------- ----------
1           aa
1           bb
2           aaa
2           bbb
2           ccc

(5 row(s) affected)
*/


--2 在SQL2000只能用自定义函数实现
----2.1 创建合并函数fn_strSum，根据id合并value值
GO
CREATE FUNCTION dbo.fn_strSum(@id int)
RETURNS varchar(8000)
AS
BEGIN
    DECLARE @values varchar(8000)
    SET @values = ''
    SELECT @values = @values + ',' + value FROM tb WHERE id=@id
    RETURN STUFF(@values, 1, 1, '')
END
GO

-- 调用函数
SELECT id, VALUE = dbo.fn_strSum(id) FROM tb GROUP BY id
DROP FUNCTION dbo.fn_strSum

----2.2 创建合并函数fn_strSum2，根据id合并value值
GO
CREATE FUNCTION dbo.fn_strSum2(@id int)
RETURNS varchar(8000)
AS
BEGIN
    DECLARE @values varchar(8000)    
    SELECT @values = isnull(@values + ',', '') + value FROM tb WHERE id=@id
    RETURN @values
END
GO

-- 调用函数
SELECT id, VALUE = dbo.fn_strSum2(id) FROM tb GROUP BY id
DROP FUNCTION dbo.fn_strSum2


--3 在SQL2005中的新解法
----3.1 使用OUTER APPLY
SELECT * 
FROM (SELECT DISTINCT id FROM tb) A OUTER APPLY(
        SELECT [values]= STUFF(REPLACE(REPLACE(
            (
                SELECT value FROM tb N
                WHERE id = A.id
                FOR XML AUTO
            ), '<N value="', ','), '"/>', ''), 1, 1, '')
)N

----3.2 使用XML
SELECT id, [values]=STUFF((SELECT ','+[value] FROM tb t WHERE id=tb.id FOR XML PATH('')), 1, 1, '')
FROM tb
GROUP BY id

--4 删除测试表tb
drop table tb

/**//*
id          values
----------- --------------------
1           aa,bb
2           aaa,bbb,ccc

(2 row(s) affected)


本文来自CSDN博客，转载请标明出处：http://blog.csdn.net/dobear_0922/archive/2008/04/22/2313839.aspx

------解决方案--------------------


------解决方案--------------------
探讨

SQL code
-- Title: 在SQL中分类合并数据行
-- Author: dobear        Mail(MSN): dobear_0922@hotmail.com
-- Environment: Vista + SQL2005
-- Date: 2008-04-22
-- ================================================……


------解决方案--------------------
1楼很多方法了。

------解决方案--------------------
SQL code
/****************************************************************************************************************************************************** 
合并分拆表数据 

整理人：中国风(Roy) 

日期:2008.06.06 
******************************************************************************************************************************************************/ 

--> --> (Roy)生成測試數據 

if not object_id('Tab') is null 
    drop table Tab 
Go 
Create table Tab([Col1] int,[Col2] nvarchar(1)) 
Insert Tab 
select 1,N'a' union all 
select 1,N'b' union all 
select 1,N'c' union all 
select 2,N'd' union all 
select 2,N'e' union all 
select 3,N'f' 
Go 

合并表: 

SQL2000用函数: 

go 
if object_id('F_Str') is not null 
    drop function F_Str 
go 
create function F_Str(@Col1 int) 
returns nvarchar(100) 
as 
begin 
    declare @S nvarchar(100) 
    select @S=isnull(@S+',','')+