--sql2005及以上版本

select *
from(
    select *,rid=row_number() over (order by age)
    from [users]
) t
where rid between @m and @n

--sql2000

select *,rid=identity(int,1,1) into #tb
from [users]
order by age

select * from #tb where rid between @m and @n

drop table #tb

------解决方案--------------------
SQL code

取n到m行

1. 
select top (n-m+1) * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/) 

2. 
select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表 
set rowcount n   --只取n条结果
select * from 表变量 order by columnname desc 

3. 
select top n * from  
(select top m * from tablename order by columnname) a 
order by columnname desc 


4.如果tablename里没有其他identity列，那么： 
先生成一个序列,存储在一临时表中.
select identity(int) id0,* into #temp from tablename 

取n到m条的语句为： 
select * from #temp where id0 > =n and id0  <= m 

如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行： 
exec sp_dboption 你的DB名字,'select into/bulkcopy',true 


5.如果表里有identity属性，那么简单： 
select * from tablename where identity_col between n and m  

6.SQL2005开始.可以使用row_number() over()生成行号
;with cte as
(
 select id0=row_number() over(order by id),* from tablename
)
select * from cte where id0 between n to m

慢慢看吧

------解决方案--------------------
这个根据实际情况来吧，我比较喜欢用row_number()over()这个

------解决方案--------------------
探讨


to TravyLee：
还是觉得row_number()好用 和oracle里面用rownum也相似（以前一直用oracle）
请教一下 上面这些方法里 哪个是最常用的或者最热门的 
谢谢