日期:2014-05-18  浏览次数:20584 次

这样的数据怎样排序,求SQL语句
有表数据:
ID F1 Qty F3
1 A1 1 001
2 A1 1 001
3 A1 2 002
4 A1 3 003
5 B1 1 004
6 B1 1 005
7 B1 1 005
8 B1 2 005
9 C1 1 006

要按:F1,Qty进行排序,然后再把具有相同的F3排在最后面,要得到以下结果:
ID F1 Qty F3
3 A1 2 002
4 A1 3 003
5 B1 1 004
9 C1 1 006
1 A1 1 001
2 A1 1 001
6 B1 1 005
7 B1 1 005
8 B1 2 005


------解决方案--------------------
SQL code

select *
from tb t
order by (case when exists (select 1 from tb where f1=t.f1 and qty=t.qty and id<>t.id) then 1 else 0 end),f1,qty,f3

------解决方案--------------------
实在没理解你的逻辑,能把你的应用说说吗?
------解决方案--------------------
SQL code

declare @T table (ID int,F1 varchar(2),Qty int,F3 varchar(3))
insert into @T
select 1,'A1',1,'001' union all
select 2,'A1',1,'001' union all
select 3,'A1',2,'002' union all
select 4,'A1',3,'003' union all
select 5,'B1',1,'004' union all
select 6,'B1',1,'005' union all
select 7,'B1',1,'005' union all
select 8,'B1',2,'005' union all
select 9,'C1',1,'006'

select * from @T t order by (select count(1) from @T where F3=t.F3)
/*
ID          F1   Qty         F3
----------- ---- ----------- ----
3           A1   2           002
4           A1   3           003
5           B1   1           004
9           C1   1           006
1           A1   1           001
2           A1   1           001
6           B1   1           005
7           B1   1           005
8           B1   2           005
*/

------解决方案--------------------
SQL code
DECLARE  @T TABLE(ID VARCHAR(20),F1 VARCHAR(20),  Qty VARCHAR(20),F3 VARCHAR(20))
INSERT INTO @T
SELECT '1','A1','1','001' UNION ALL
SELECT '2','A1','1','001' UNION ALL
SELECT '3','A1','2','002' UNION ALL
SELECT '4','A1','3','003' UNION ALL
SELECT '5','B1','1','004' UNION ALL
SELECT '6','B1','1','005' UNION ALL
SELECT '7','B1','1','005' UNION ALL
SELECT '8','B1','2','005' UNION ALL
SELECT '9','C1','1','006'

SELECT *
FROM (
SELECT (SELECT COUNT(1) FROM @T WHERE F3=T1.F3 GROUP BY F3) AS ORD, * 
FROM @T T1
) A
ORDER BY ORD,F1,QTY

------解决方案--------------------
SQL code
create table tb (ID int,F1 varchar(2),Qty int,F3 varchar(3))
insert into tb
select 1,'A1',1,'001' union all
select 2,'A1',1,'001' union all
select 3,'A1',2,'002' union all
select 4,'A1',3,'003' union all
select 5,'B1',1,'004' union all
select 6,'B1',1,'005' union all
select 7,'B1',1,'005' union all
select 8,'B1',2,'005' union all
select 9,'C1',1,'006'

select m.* from tb m , (
select f3 , count(1) cnt from tb group by f3) n
where m.f3 = n.f3
order by n.cnt , m.f1 , m.qty

drop table tb

/*
ID          F1   Qty         F3   
----------- ---- ----------- ---- 
3           A1   2           002
4           A1   3           003
5           B1   1           004
9           C1   1           006
1           A1   1           001
2           A1   1           001
6           B1   1           005
7           B1   1           005
8           B1   2           005

(所影响的行数为 9 行)
*/