日期:2014-05-18  浏览次数:20449 次

急 很急 急得很 救命~~!
为表写一个通用存储过程,传入表具编号(MeterNo)和日期(Dt),可以返回该表的24小时的数据(1—24小时,24条记录),数值(Qty)保留两位小数。


表如下:
DANo(char(32),not null)
MeterNo(char(20),not null)
MeterType(char(4),not null)
DATime(datetime,not null)
LogTime(datetime,not null)
DAType(char(3),null)
Qty(decimal(18,6),not null)
Qty01(decimal(18,6),not null)
Qty02(decimal(18,6),null)
Note(nvarchar(50),null)



------解决方案--------------------
SQL code
create proc procname
@MeterNo varchar(50),
@DataTime datetime,
@Qty dec(18,2) output
as
 select @Qty=Qty
 from tb
 where MeterNo=@MeterNo and [DataTime]=@DataTime

------解决方案--------------------
SQL code

create proc procname
(
    @meterno varchar(50),
    @datatime datetime
)
as
begin
    select datepart(hour,getdate()),cast(sum(qty) as decimal(18,2))
    from tablename
    where meterno=@meterno 
    and convert(varchar(10),[datatime],120)=convert(varchar(10),@datatime,120)
    group by datepart(hour,getdate())
end