create table t1(id int,name varchar(10))
insert t1
select 1, '严二' union all
select 2, '严三' union all
select 3, '严二' union all
select 4, '严五' union all
select 5, '严二'
go
select * from t1 a
where exists(select 1 from t1 where a.name=name and a.id<>id)
/*
id  name
--  ----
1    严二
3    严二
5    严二
*/
go
drop table t1

------解决方案--------------------
SQL code
declare @t table (id int, name nvarchar(10))
insert into @t
select 1 ,'严二' union 
select 2 ,'严三' union 
select 3 ,'严二' union 
select 4 ,'严五' union 
select 5 ,'严二'

;
with t
as(
select row_number() over(partition by name order by name) as num ,id,name from @t)
select id,name from t where name in(select name from t where num>1 )

------解决方案--------------------
SQL code

查找所有重复标题的记录：

SELECT *
FROM t_info a
WHERE ((SELECT COUNT(*)
          FROM t_info
          WHERE Title = a.Title) > 1)
ORDER BY Title DESC

一。查找重复记录

1。查找全部重复记录

Select * From 表 Where 重复字段 In (Select 重复字段 From 表 Group By 重复字段 Having Count(*)>1)

2。过滤重复记录(只显示一条)

Select * From HZT Where ID In (Select Max(ID) From HZT Group By Title)

注：此处显示ID最大一条记录

二。删除重复记录


1。删除全部重复记录（慎用）

Delete 表 Where 重复字段 In (Select 重复字段 From 表 Group By 重复字段 Having Count(*)>1)

2。保留一条（这个应该是大多数人所需要的 ^_^）

Delete HZT Where ID Not In (Select Max(ID) From HZT Group By Title)

注：此处保留ID最大一条记录

1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断

select * from people

where peopleId in (select   peopleId from   people group by   peopleId having count(peopleId) > 1)



2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录

delete from people 

where peopleId in (select   peopleId from people group by   peopleId   having count(peopleId) > 1)

and rowid not in (select min(rowid) from   people group by peopleId having count(peopleId )>1)



3、查找表中多余的重复记录（多个字段） 

select * from vitae a

where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)



4、删除表中多余的重复记录（多个字段），只留有rowid最小的记录

delete from vitae a

where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)



5、查找表中多余的重复记录（多个字段），不包含rowid最小的记录

select * from vitae a

where (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)


补充：

有两个以上的重复记录，一是完全重复的记录，也即所有字段均重复的记录，二是部分关键字段重复的记录，比如Name字段重复，而其他字段不一定重复或都重复可以忽略。



1、对于第一种重复，比较容易解决，使用

select distinct * from tableName



就可以得到无重复记录的结果集。



如果该表需要删除重复的记录（重复记录保留1条），可以按以下方法删除

select distinct * into #Tmp from tableName

drop table tableName

select * into tableName from #Tmp

drop table #Tmp



发生这种重复的原因是表设计不周产生的，增加唯一索引列即可解决。



2、这类重复问题通常要求保留重复记录中的第一条记录，操作方法如下



假设有重复的字段为Name,Address，要求得到这两个字段唯一的结果集

select identity(int,1,1) as autoID, * into #Tmp from tableName

select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID

select * from #Tmp where autoID in(select autoID from #tmp2)



最后一个select即得到了Name，Address不重复的结果集（但多了一个autoID字段，实际写时可以写在select子句中省去此列）