日期:2014-05-18 浏览次数:20549 次
DECLARE @tb Table( CompanyID INT, CompanyCodes VARCHAR(100) ) insert into @tb select 1,'1|2' union all select 2,'1|2|3' union all select 3,'1|2|3|4' union all select 4,'1|2|3|4|5' select a.CompanyID, CompanyCodes = substring(a.CompanyCodes,b.number,charindex('|',a.CompanyCodes+'|',b.number)-b.number) from @tb a join master..spt_values b on b.[type] = 'p' and b.number between 0 and len(a.CompanyCodes) and substring('|'+a.CompanyCodes,b.number,1) = '|' /**************** CompanyID CompanyCodes ----------- ---------------------------------------------------------------- 1 1 1 2 2 1 2 2 2 3 3 1 3 2 3 3 3 4 4 1 4 2 4 3 4 4 4 5 (14 行受影响)
------解决方案--------------------
DECLARE @tb Table(
F1 varchar(12),
F2 VARCHAR(100)
)
insert into @tb select 'a','1,2,5'
union all select 'b','1,3'
union all select 'c','3,5'
select a.F1,b.vx
from
(select F1,cast('<root><v>'+REPLACE(F2,',','</v><v>')+'</v></root>' as xml) as x from @tb) a
outer apply(
select vx=N.v.value('.','varchar(100)') from a.x.nodes('/root/v') N(v)
) b
------解决方案--------------------
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create table tb(F1 char(1),F2 varchar(10)) insert into tb select 'a','1,2,5' union select 'b','1,3' union select 'c','3,5' create function f(@str varchar(20)) returns @t table (F varchar(2)) as begin set @str=@str+',' while CHARINDEX(',',@str)>0 begin insert into @t select left(@str,CHARINDEX(',',@str)-1) set @str=right(@str,len(@str)-CHARINDEX(',',@str)) end return end select a.F1,b.* from tb a cross apply f(a.F2)b /