日期:2014-05-18  浏览次数:20658 次

兼容语句问题
SQL code
SELECT 
    表名       = case when a.colorder=1 then d.name else '' end,
    表说明     = case when a.colorder=1 then isnull(f.value,'') else '' end,
    字段序号   = a.colorder,
    字段名     = a.name,
    标识       = case when COLUMNPROPERTY( a.id,a.name,'IsIdentity')=1 then '√'else '' end,
    主键       = case when exists(SELECT 1 FROM sysobjects where xtype='PK' and parent_obj=a.id and name in (
                     SELECT name FROM sysindexes WHERE indid in(SELECT indid FROM sysindexkeys WHERE id = a.id AND colid=a.colid))) then '√' else '' end,
    类型       = b.name,
    占用字节数 = a.length,
    长度       = COLUMNPROPERTY(a.id,a.name,'PRECISION'),
    小数位数   = isnull(COLUMNPROPERTY(a.id,a.name,'Scale'),0),
    允许空     = case when a.isnullable=1 then '√'else '' end,
    默认值     = isnull(e.text,''),
    字段说明   = isnull(g.[value],'')
FROM 
    syscolumns a
left join 
    systypes b 
on 
    a.xusertype=b.xusertype
inner join 
    sysobjects d 
on 
    a.id=d.id and d.xtype='U' and d.name<>'dtproperties'
left join 
    syscomments e 
on 
    a.cdefault=e.id
left join 
    sysproperties g 
on 
    a.id=g.id and a.colid=g.smallid 
left join 
    sysproperties f 
on 
    d.id=f.id and f.smallid=0
where 
    d.name='tablename'    --如果只查询指定表,加上此条件
order by 
    a.id,a.colorder


上面这段语句只支持sql2005,sql2008.不支持sql2000,能将之改成通用的

------解决方案--------------------
看题看了下
应该本身就是写给2000的环境的
没有2000环境 没的测试
报错的提示是什么
------解决方案--------------------
可以在2000下用,显示表结构的,要将'tablename' 改为自已要查的表名称