同一个存储过程中如何把两个不同条件查询的值再相加
日期：2014-05-18 浏览次数：20671 次
同一个存储过程中怎么把两个不同条件查询的值再相加
这两个查询的结果怎么再对应列再相加起来?
------解决方案--------------------
相加?
是这样么:
- SQL code
ALTER PROCEDURE dbo.StockCount
(
@CompanyID int = 5
)
AS
Begin
SELECT
SUM(CASE WHEN TypeID=1 THEN m8 ELSE -m8 END) AS m8,
SUM(CASE WHEN TypeID=1 THEN m9 ELSE -m9 END) AS m9,
SUM(CASE WHEN TypeID=1 THEN m10 ELSE -m10 END) AS m10,
SUM(CASE WHEN TypeID=1 THEN m11 ELSE -m11 END) AS m11,
SUM(CASE WHEN TypeID=1 THEN m12 ELSE -m12 END) AS m12,
SUM(CASE WHEN TypeID=1 THEN m13 ELSE -m13 END) AS m13,
SUM(CASE WHEN TypeID=1 THEN m14 ELSE -m14 END) AS m14,
SUM(CASE WHEN TypeID=1 THEN m15 ELSE -m15 END) AS m15,
SUM(CASE WHEN TypeID=1 THEN m16 ELSE -m16 END) AS m16
FROM RLStock
where Status in(1,2) and CompanyID=@CompanyID
-----------
SELECT
SUM(m8) AS m8,
SUM(m9) AS m9,
SUM(m10) AS m10,
SUM(m11) AS m11,
SUM(m12) AS m12,
SUM(m13) AS m13,
SUM(m14) AS m14,
SUM(m15) AS m15,
SUM(m16) AS m16
FROM RLStock
where Status=4 and TypeID=3 and ToCompanyID=@CompanyID
END
这两个查询的结果怎么再对应列再相加起来?
------解决方案--------------------
相加?
是这样么:
- SQL code
select sum(m8)m8,sum(m9)m9,sum(m10)m10,sum(m11)m11,sum(m12)m12,sum(m13)m13,sum(m14)m14,sum(m15)m15,sum(m16)m16
from(
SELECT
SUM(CASE WHEN TypeID=1 THEN m8 ELSE -m8 END) AS m8,
SUM(CASE WHEN TypeID=1 THEN m9 ELSE -m9 END) AS m9,
SUM(CASE WHEN TypeID=1 THEN m10 ELSE -m10 END) AS m10,
SUM(CASE WHEN TypeID=1 THEN m11 ELSE -m11 END) AS m11,
SUM(CASE WHEN TypeID=1 THEN m12 ELSE -m12 END) AS m12,
SUM(CASE WHEN TypeID=1 THEN m13 ELSE -m13 END) AS m13,
SUM(CASE WHEN TypeID=1 THEN m14 ELSE -m14 END) AS m14,
SUM(CASE WHEN TypeID=1 THEN m15 ELSE -m15 END) AS m15,
SUM(CASE WHEN TypeID=1 THEN m16 ELSE -m16 END) AS m16
FROM RLStock
where Status in(1,2) and CompanyID=@CompanyID
union all
SELECT
SUM(m8) AS m8,
SUM(m9) AS m9,
SUM(m10) AS m10,
SUM(m11) AS m11,
SUM(m12) AS m12,
SUM(m13) AS m13,
SUM(m14) AS m14,
SUM(m15) AS m15,
SUM(m16) AS m16
FROM RLStock
where Status=4 and TypeID=3 and ToCompanyID=@CompanyID
)t
END
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