select * from T1 a where not exists(select 1 from T1 where name=a.name and recordTime>a.recordTime)

------解决方案--------------------
row_number()over(partition by order by )

------解决方案--------------------
SQL code
select * from t1 a where not exists(select 1 from t1 where abs(datediff(mi,recordtime,getdate()))<abs(datediff(mi,a.recordtime,getdate()))

------解决方案--------------------
SQL code

select top 1 * from t1 order by recordTime desc

------解决方案--------------------
和 当前日期做 差，取差值最小的

------解决方案--------------------
select DATEDIFF(ms,GETDATE(),getdate()+1)---毫秒
select DATEDIFF(day,GETDATE(),getdate()+1)---天
select DATEDIFF(HOUR,GETDATE(),getdate()+1)---小时
select DATEDIFF(Minute,GETDATE(),getdate()+1)---分钟
select DATEDIFF(Second,GETDATE(),getdate()+1)---秒