日期:2014-05-18 浏览次数:20600 次
ip address 192.168.1.1 aaa 192.168.1.2 蜘蛛A 192.168.1.2 蜘蛛A 192.168.1.2 蜘蛛A 192.168.1.3 蜘蛛B 192.168.1.3 蜘蛛B 192.168.1.4 www.123.com 192.168.1.4 www.123.com 192.168.1.5 www.abc.com 192.168.1.6 www.ff.com 192.168.1.6 www.abc.com
select count(distinct ip) from tb where address not like '%蜘蛛%' or address not like '%12%'
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select ip,sum(case when charindex('蜘蛛',address)=0 or charindex('12',address)=0 then 0 else 1 end) as cnt
from tb
group by ip
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select distinct ip from tablename where charindex('蜘蛛',address)<0 and charindex('12',address)<0
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create table tb(ip varchar(20),address varchar(50)) insert into tb select '192.168.1.1' , 'aaa' union all select '192.168.1.2' , '蜘蛛A' union all select '192.168.1.2' , '蜘蛛A' union all select '192.168.1.2' , '蜘蛛A' union all select '192.168.1.3' , '蜘蛛B' union all select '192.168.1.3' , '蜘蛛B' union all select '192.168.1.4' , 'www.123.com' union all select '192.168.1.4' , 'www.123.com' union all select '192.168.1.5' , 'www.abc.com' union all select '192.168.1.6' , 'www.ff.com' union all select '192.168.1.6' , 'www.abc.com' select * from tb select count(distinct ip) from tb where address not like '%蜘蛛%' and address not like '%12%' /* 3 */ select ip from tb where address not like '%蜘蛛%' and address not like '%12%' group by ip /* 192.168.1.1 192.168.1.5 192.168.1.6 */
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上面的 条件 or 改为 and
用 or 是错的
------解决方案--------------------
用charindex 或 patindex 或 like 都可以
select count(distinct IP) from tableName where patindex('%12%',address)=0 and patindex('%蜘蛛%',address)=0
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if object_id('tb') is not null drop table tb go create table tb ( ip varchar(20), address varchar(20) ) go insert into tb select '192.168.1.1','aaa' union all select '192.168.1.2','蜘蛛A' union all select '192.168.1.2','蜘蛛A' union all select '192.168.1.2','蜘蛛A' union all select '192.168.1.3','蜘蛛B' union all select '192.168.1.3','蜘蛛B' union all select '192.168.1.4','www.123.com' union all select '192.168.1.4','www.123.com' union all se