日期:2014-05-18  浏览次数:20613 次

这样的查询语句怎么最好?比较特殊
表Test结构为两个字段,id与timedate,id为自动增长,timedate为时间,id唯一,时间,有可能会相同,也有可能为空。
现已知id值,我要通过id查询一条记录,查询规则为按时间降序,id降序的下一条记录,
select * from Test order by timedate desc,id desc 即按条语句查询结果,找出该id所在记录的下一条记录。
测试数据如下:
id timedate
1 2011-7-11 0:00:00
2 2011-6-11 0:00:00
3 2011-6-11 0:00:00
4 2011-6-11 0:00:00
5 2011-9-11 0:00:00
6 2011-5-11 0:00:00

通过select * from Test order by timedate desc,id desc 排序后:
id timedate
5 2011-9-11 0:00:00
1 2011-7-11 0:00:00
4 2011-6-11 0:00:00
3 2011-6-11 0:00:00
2 2011-6-11 0:00:00
6 2011-5-11 0:00:00
现在我想实现的是这样的:
如果id=4,那么,我想查到id=3这条记录,
如果id=3,那么,我想查到id=2这条记录,
如果id=2,那么,我想查到id=6这条记录

该怎么写呢?下面这样写不行:select * from Test where id = 4 and timedate <= (select timedate from Test where id=4)

这个看起来简单,没想到,试了半天没试出来,请各位大虾帮忙了,先谢了。

------解决方案--------------------
SQL code
----------------------------
-- Author  :fredrickhu(小F,向高手学习)
-- Date    :2011-12-26 14:53:26
-- Version:
--      Microsoft SQL Server 2008 R2 (RTM) - 10.50.1617.0 (Intel X86) 
--    Apr 22 2011 11:57:00 
--    Copyright (c) Microsoft Corporation
--    Enterprise Evaluation Edition on Windows NT 6.1 <X64> (Build 7600: ) (WOW64)
--
----------------------------
--> 测试数据:[tb]
if object_id('[tb]') is not null drop table [tb]
go 
create table [tb]([id] int,[timedate] datetime)
insert [tb]
select 1,'2011-7-11 0:00:00' union all
select 2,'2011-6-11 0:00:00' union all
select 3,'2011-6-11 0:00:00' union all
select 4,'2011-6-11 0:00:00' union all
select 5,'2011-9-11 0:00:00' union all
select 6,'2011-5-11 0:00:00'
--------------开始查询--------------------------
;with f as
(
select px=ROW_NUMBER()over(order by timedate desc,id desc),* from tb
)

select id,timedate from f where px=(select px+1 from f where ID=3)

----------------结果----------------------------
/*id          timedate
----------- -----------------------
2           2011-06-11 00:00:00.000

(1 行受影响)
*/

------解决方案--------------------
http://blog.csdn.net/ACMAIN_CHM/archive/2009/04/20/4095531.aspx

mysql参考上面的这个
------解决方案--------------------
try this,
SQL code

declare @x int

select @x:=ifnull(@x,0)+1 as rownum,id,timedate
into #t
from tab
order by timedate desc,id desc

select * from #t where rownum=
(select rownum+1 from #t where id=[指定的id])

drop table #t

------解决方案--------------------
SQL code
create table tb(id int,timedate datetime)
insert into tb select 1,'2011-7-11 0:00:00'
insert into tb select 2,'2011-6-11 0:00:00'
insert into tb select 3,'2011-6-11 0:00:00'
insert into tb select 4,'2011-6-11 0:00:00'
insert into tb select 5,'2011-9-11 0:00:00'
insert into tb select 6,'2011-5-11 0:00:00'
go
declare @id int
set @id=2
select top 1 * 
from tb a
where timedate<(select timedate from tb where id=@id)
or id<(select top 1 id from tb where timedate=a.timedate and id<=@id order by id desc)
order by timedate desc,id desc
/*
id          timedate
----------- -----------------------
6           2011-05-11 00:00:00.000

(1 行受影响)

*/
go
drop table tb

------解决方案--------------------
MSSQL2005及以上:
SQL code

 create table tb(id int,timedate datetime)
insert into tb select 1,'2011-7-11 0:00:00';
insert into tb select 2,'2011-6-11 0:00:00';
insert into tb select 3,'2011-6-11 0:00:00';
insert into tb select 4,'2011-6-11 0:00:00';
insert into tb select 5,'2011-9-11 0:00:00';
insert into tb select 6,'2011-5-11 0:00:00';
go
;WITH cte_1 AS (
SELECT ROW_NUMBER() OVER (ORDER BY timedate DESC,id DESC) AS rn,id
FROM dbo.tb)
SELECT * FROM cte_1 AS A WHERE rn=(SELEC