同志们啊,快帮我看看这个触发器,怎么每次出发完植都是空的!!
alter   TRIGGER   sum_gz   ON   [dbo].[jjjlb]  
FOR   INSERT,   UPDATE,   DELETE  
AS
declare   @dailiao_day_salary   float
declare   @sub_salary   float
declare   @total   float

declare   cur_total   cursor   for
select   rq,bh,ppo   from   inserted
open   cur_total
declare   @rq   varchar(10)
declare   @bh   varchar(50)
declare   @ppo   varchar(50)
fetch   next   from   cur_total   into   @rq,@bh,@ppo
while   (@@fetch_status <> -1)
begin
set   @sub_salary=(select   jbsx   from   ryda   where   bh=@bh)
set   @dailiao_day_salary=(select   dlrx   from   ryda   where   bh=@bh)
SET   @total=(select   sum(sum_sigle)   from   jjjlb   where   bh=@bh   and   rq=@rq   and   ppo=@ppo   )

update   jjjlb   set   sum_sigle=(@sub_salary/208*jssj+@sub_salary/208*1.5+@sub_salary/208*zlbgs+@sub_salary/208*jbsj_b*2+@sub_salary/208*zrbgs+@sub_salary/208*zrbgs*2+yxb_a*2+yxb_a*3)  
where   bh=@bh   and   rq=@rq   and   ppo=@ppo
update   jjjlb   set   total=@total   where   bh=@bh   and   rq=@rq   and   ppo=@ppo
fetch   next   from   cur_total   into   @rq,@bh,@ppo
end
close   cur_total
deallocate   cur_total


------解决方案--------------------
set @sub_salary=(select jbsx from ryda where bh=@bh)
set @dailiao_day_salary=(select dlrx from ryda where bh=@bh)
SET @total=(select sum(sum_sigle) from jjjlb where bh=@bh and rq=@rq and ppo=@ppo )

--〉
set @sub_salary=isnull((select jbsx from ryda where bh=@bh),0)
set @dailiao_day_salary=isnull((select dlrx from ryda where bh=@bh),0)
SET @total=isnull((select sum(sum_sigle) from jjjlb where bh=@bh and rq=@rq and ppo=@ppo ),0)


------解决方案--------------------
把
while (@@fetch_status <> -1)
改成
while (@@fetch_status=0)试试
------解决方案--------------------
把游标内的处理过程修改一下试试:
while(@@fetch_status = 0)
begin
select @sub_salary = isnull(jbsx,0), @dailiao_day_salary = isnull(dlrx,0)
from ryda where bh=@bh
select @total = isnull(sum(sum_sigle),0)
from jjjlb where bh=@bh and rq=@rq and ppo=@ppo

update jjjlb set
sum_sigle=(ISNULL(@sub_salary/208*jssj,0)+@sub_salary/208*1.5+
ISNULL(@sub_salary/208*zlbgs,0)+
ISNULL(@sub_salary/208*jbsj_b*2,0)+
ISNULL(@sub_salary/208*zrbgs,0)+
ISNULL(@sub_salary/208*zrbgs*2,0)+
ISNULL(yxb_a*2,0)+
ISNULL(yxb_a*3,0))
where bh=@bh and rq=@rq and ppo=@ppo
...
------解决方案--------------------
是青青嗎
------解决方案--------------------
現在在哪里啊
------解决方案--------------------
如果hellowork(一两清风)大哥，說的，改了沒用的話，
把FOR INSERT, UPDATE, DELETE
改為after INSERT, UPDATE, DELETE 試試