日期:2014-05-18  浏览次数:20606 次

SQL请教,这里人气旺
IDX   CODE   DEPTCODE   PARTNAME
--------------------
1   CN00001   CN00001001   PART1
2   CN00001   CN00001002   PART2
3   CN00001   CN00001001001   PART3
4   CN00001   CN00001002001   PART4
5   CN00002   CN00002001   PART5
6   CN00002   CN00002001001   PART6


IDX   CODE   DEPTCODE   DETAIL
-----------------------------------------------
1   CN00001   CN0001001   CN0001001;PART1|CN0001001001;PART3
2   CN00001   CN0001002   CN0001002;PART2|CN0001002001;PART4
3   CN00002   CN0002001   CN0002001;PART5|CN0002001001;PART6


DEPTCODE是部门代码,规则是CODE+3位为第一级部门,以此类推,下级部门在上级部门代码上加3位
我想要的结果是只是列出第一级部门信息,下级部门信息归类成为DETAIL字段,请大侠指点;


上面是原数据,下面是希望得到的结果,

理论上有无穷多层级。


有一个帖子,有哥们回答:

insert   ta   select   1,   'CN00001 ',   'CN00001001 '   ,   'PART1 '
union   all   select   2,   'CN00001 ',   'CN00001002 ',   'PART2 '
union   all   select   3,   'CN00001 ',   'CN00001001001 ',   'PART3 '
union   all   select   4,   'CN00001 ',   'CN00001002001 ',   'PART4 '
union   all   select   5,   'CN00002 ',   'CN00002001 ',   'PART5 '
union   all   select   6,   'CN00002 ',   'CN00002001001 ',   'PART6 '

改一下:
create   function   test_f(@DEPTCODE   varchar(50))
returns   varchar(100)
as
begin
declare   @s   varchar(100)
select   @s=isnull(@s, ' ')+DEPTCODE+ ': '+PARTNAME+ '| '   from   ta   where   charindex(@DEPTCODE,DEPTCODE)=1
return   left(@s,len(@s)-1)
end

select   IDX,CODE,DEPTCODE   ,显示=dbo.test_f(DEPTCODE)   from   ta   where   len(dbo.test_f(DEPTCODE))> 21
1CN00001CN00001001CN00001001:PART1|CN00001001001:PART3
2CN00001CN00001002CN00001002:PART2|CN00001002001:PART4
5CN00002CN00002001CN00002001:PART5|CN00002001001:PART6


可以运行,但改成

create   function   test_f(@DEPTCODE   varchar(50))
returns   varchar(7000)
as
begin
declare   @s   varchar(7000)
select   @s=isnull(@s, ' ')+DEPTCODE+ ': '+PARTNAME+ '| '   from   ta   where   charindex(@DEPTCODE,DEPTCODE)=1     and   status <> 0
return   left(@s,len(@s)-1)
end

运行报错,说传入的参数长度错误,只是多了一点
and   status <> 0     呀

status是表里面的一个整型字段,

大虾们有什么高招,请教

------解决方案--------------------
create table ta(IDX int, CODE varchar(20), DEPTCODE varchar(50), PARTNAME varchar(20), status int)
insert ta select 1, 'CN00001 ', 'CN00001001 ', 'PART1 ', 2
union all select 2, 'CN00001 ', 'CN00001002 ', 'PART2 ', 0
union all select 3, 'CN00001 ', 'CN00001001001 ', 'PART3 ', 1
union all select 4, 'CN00001 ', 'CN00001002001 ', 'PART4 ', 2
union all select 5, 'CN00002 ', 'CN00002001 ', 'PART5 ', 2
union all select 6, 'CN00002 ', 'CN00002001001 ', 'PART6 ', 1