日期:2014-05-18 浏览次数:20589 次
create table t1(Col1 varchar(10), col2 varchar(10)) insert into t1 values('A1','A-1') insert into t1 values('B2','A-2') insert into t1 values('C2','D-1') create table t2(Col1 varchar(10), col2 varchar(30)) insert into t2 values('E-2019N','A1-平面纹') insert into t2 values('E-2019N','60036-B2-平面纹') insert into t2 values('E-2019N','B2-AE-80012-平面纹') insert into t2 values('E-2019N','B2-AE-80012-平面纹') insert into t2 values('E-2019N','AE-C2-80012-平面纹') insert into t2 values('E-2019N','AE-80012-C2-平面纹') go --search select t2.col1,col2 = replace(t2.col2,t1.col1,t1.col2) from t1,t2 where charindex(t1.col1,t2.col2) > 0 /* col1 col2 ---------- ------------------ E-2019N A-1-平面纹 E-2019N 60036-A-2-平面纹 E-2019N A-2-AE-80012-平面纹 E-2019N A-2-AE-80012-平面纹 E-2019N AE-D-1-80012-平面纹 E-2019N AE-80012-D-1-平面纹 (所影响的行数为 6 行) */ --update update t2 set col2 = replace(t2.col2,t1.col1,t1.col2) from t1,t2 where charindex(t1.col1,t2.col2) > 0 select * from t2 /* col1 col2 ---------- ------------------ E-2019N A-1-平面纹 E-2019N 60036-A-2-平面纹 E-2019N A-2-AE-80012-平面纹 E-2019N A-2-AE-80012-平面纹 E-2019N AE-D-1-80012-平面纹 E-2019N AE-80012-D-1-平面纹 (所影响的行数为 6 行) */ drop table t1,t2
------解决方案--------------------
declare @table1 table (col1 varchar(2), col2 varchar(3)) insert into @table1 select 'A1','A-1' union select 'B2','A-2' union select 'C2','D-1' declare @table2 table (col1 varchar(7), col2 varchar(50)) insert into @table2 select 'E-2019N', 'A1-pmw' union select 'E-2019N', '60036-B2-pmw' union select 'E-2019N', 'B2-AE-80012-pmw' union select 'E-2019N', 'B2-AE-80012-pmw' union select 'E-2019N', 'AE-C2-80012-pmw' union select 'E-2019N', 'AE-80012-C2-pmw' select * from @table1 select * from @table2 update y set y.col2 = replace(y.col2, x.col1, x.col2) from @table1 x, @table2 y where y.col2 like '%' + x.col1 + '%' select * from @table2