declare @s varchar(8000),@next int     
set @s=')((()as(d(s())))'     
declare @ntb table(id int ,name varchar(10),next int)      
declare @stb table(id int identity(1,1),name varchar(10))      
set @next=1      
/*模拟循环链表*/     
while (@s is not null)      
begin      
   insert into @ntb values(@next,left(@s,1),@next+1)      
   select @s=stuff(@s,1,1,''),@next=@next+1      
end      
update @ntb      
set next=1      
where id=@next-1      
select * from @ntb   
/*模拟栈并进行判断*/     
declare @nextNode int,@c char ,@id int    
select top 1 @id=id,@c=name,@nextnode=next from @ntb order by id      
while @nextnode<>(select min(id) from @ntb)      
begin       
    if @c='('        
      begin       
        insert into @stb values(@c)     
      end        
   if @c=')'     
   begin      
         if exists(select 1 from @stb)      
            begin      
               delete from @stb       
               where id=(select max(id) from @stb)      
            end      
         else     
            break     
      end      
    select @id=id,@c=name ,@nextnode=next from @ntb where id=@nextnode      
end      
if exists(select 1 from @stb)      
   print'左括号不匹配'     
else     
  if exists(select 1 from @ntb where id>@id )      
      print '右括号不匹配'     
  else     
      print '匹配'     
结果：   
右括号不匹配