-------合并表-------
/****************************************************************************************************************************************************** 
合并分拆表数据 

整理人：中国风(Roy) 

日期:2008.06.06 
******************************************************************************************************************************************************/ 

--> --> (Roy)生成測試數據 

if not object_id('Tab') is null 
    drop table Tab 
Go 
Create table Tab([Col1] int,[Col2] nvarchar(1)) 
Insert Tab 
select 1,N'a' union all 
select 1,N'b' union all 
select 1,N'c' union all 
select 2,N'd' union all 
select 2,N'e' union all 
select 3,N'f' 
Go 

合并表: 

SQL2000用函数: 

go 
if object_id('F_Str') is not null 
    drop function F_Str 
go 
create function F_Str(@Col1 int) 
returns nvarchar(100) 
as 
begin 
    declare @S nvarchar(100) 
    select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1 
    return @S 
end 
go 
Select distinct Col1,Col2=dbo.F_Str(Col1) from Tab 

go 

SQL2005用XML: 

方法1: 

select 
    a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'') 
from 
    (select distinct COl1 from Tab) a 
Cross apply 
    (select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b 

方法2: 

select 
    a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44)) 
from 
    (select distinct COl1 from Tab) a 
cross apply 
    (select Col2=(select COl2 from Tab  where COl1=a.COl1 FOR XML AUTO, TYPE) 
                .query(' <Tab> 
                {for $i in /Tab[position() <last()]/@COl2 return concat(string($i),",")} 
                {concat("",string(/Tab[last()]/@COl2))} 
                </Tab>') 
                )b 

SQL05用CTE: 

;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab) 
,Roy2 as 
(select COl1,cast(COl2 as nvarchar(100))COl2,row from Roy where row=1 
union all 
select a.Col1,cast(b.COl2+','+a.COl2 as nvarchar(100)),a.row from Roy a join Roy2 b on a.COl1=b.COl1 and a.row=b.row+1) 
select Col1,Col2 from Roy2 a where row=(select max(row) from roy where Col1=a.COl1) order by Col1 option (MAXRECURSION 0) 


生成结果: 
/* 
Col1        COl2 
----------- ------------ 
1          a,b,c 
2          d,e 
3          f 

(3 行受影响) 
*/

------解决方案--------------------
探讨

引用:
行列转换是吧！


恩，是的，在sqlserver里面如何用一句sql搞定呢？


------解决方案--------------------
SQL code
if object_id('tb') is not null drop table tb
create table tb(检验员  varchar(10), 打印日期 nvarchar(10),  漏检次数 int)
go
insert tb select '罗邦卫','2009-7-31',2 
insert tb select '梅强','2009-7-31',2 
insert tb select '周林江','2009-7-31',1 
insert tb select '周强','2009-7-31',3 
insert tb select '陈刚','2009-8-1',1 
insert tb select '陈华林','2009-8-1',2 
insert tb select '董加军','2009-8-1',1 
insert tb select '罗邦卫','2009-8-1',2 
insert tb select '方文祥','2009-8-1',2 
insert tb select '周林江','2009-8-1',2 
insert tb select '周强','2009-8-1',1 
insert tb select '陈刚','2009-8-3',1 
insert tb select '陈华林','2009-8-3', 1 
insert tb select '陈杰','2009-8-3',3 
insert tb select '李林峰','2009-8-3',1 
go



declare @sql nvarchar(4000)
set @sql='select 检验员'   --变量必须初始化赋值

select @sql=@sql+
                 N','+quotename(打印日期)+
                 N'=max(case 打印日期 when '+quotename(打印日期,N'''')+  --quotename(打印日期)=[打印日期],打印日期(打印日期,N'''')='2009-8-3'......
                 N' then 漏检次数 else 0 end)'
       from tb group by 打印日期  --按日期