日期:2014-05-18  浏览次数:20700 次

SQL 拼接字符串
SQL code

declare @a nvarchar(50),@b nvarchar(50)
set @a = ' 12:12 13:13 ',@b = ' 12:12 13:45 20:22 '


如何按时间顺序用一条SQL语句拼接出不重复的时间字符串呢?
结果如下:
' 12:12 13:13 13:45 20:22 '

求高手们帮忙!非常感谢!!

------解决方案--------------------
拆分成列,distinct, 再组合成行。

------解决方案--------------------
SQL code
declare @a nvarchar(50),@b nvarchar(50)
select @a = ' 12:12 13:13 ',@b = ' 12:12 13:45 20:22 '

SELECT REPLACE(
(SELECT DISTINCT ','+ NULLIF(substring(a.col,b.number,charindex(' ',a.col+' ',b.number)-b.number),' ') 
FROM (SELECT LTRIM(@a+@b) AS col)a,master.dbo.spt_values AS b
WHERE b.type='P' AND CHARINDEX(' ',' '+a.Col,b.number)=b.number
FOR XML PATH (''))
,',',' ')

/*
 12:12 13:13 13:45 20:22*/

------解决方案--------------------
SQL code
declare @a nvarchar(50),@b nvarchar(50)
set @a = '12:12 13:13 '
set @b = '12:12 13:45 20:22 '


set @b=right(@b,len(@b)-charindex(' ',@b)+1)
set @a=@a+@b
print @a

---结果
--12:12 13:13 13:45 20:22

------解决方案--------------------
SQL code

declare @a nvarchar(50),@b nvarchar(50),@c nvarchar(50)
set @a = ' 12:12 13:13 '
set @b = ' 12:12 13:45 20:22 '
set @a = replace(ltrim(rtrim(@a)),' ',',')
set @b = replace(ltrim(rtrim(@b)),' ',',')
select @c = isnull(@c+',','') + cnt
from(select distinct substring(@a+','+@b,number,charindex(',',@a+','+@b+',',number)-number) cnt
    from master..spt_values
    where [type] = 'p' and number between 0 and len(@a+','+@b)
        and substring(','+@a+','+@b,number,1) = ','
)t
select ' '+replace(@c,',',' ')+' '

/*************

----------------------------------------------------------------------------------------------------------------
 12:12 13:13 13:45 20:22 

(1 行受影响)

------解决方案--------------------
SQL code
/****************************************************************************************************************************************************** 
合并分拆表数据 

整理人:中国风(Roy) 

日期:2008.06.06 
******************************************************************************************************************************************************/ 

--> --> (Roy)生成測試數據 

if not object_id('Tab') is null 
    drop table Tab 
Go 
Create table Tab([Col1] int,[Col2] nvarchar(1)) 
Insert Tab 
select 1,N'a' union all 
select 1,N'b' union all 
select 1,N'c' union all 
select 2,N'd' union all 
select 2,N'e' union all 
select 3,N'f' 
Go 

合并表: 

SQL2000用函数: 

go 
if object_id('F_Str') is not null 
    drop function F_Str 
go 
create function F_Str(@Col1 int) 
returns nvarchar(100) 
as 
begin 
    declare @S nvarchar(100) 
    select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1 
    return @S 
end 
go 
Select distinct Col1,Col2=dbo.F_Str(Col1) from Tab 

go 

SQL2005用XML: 

方法1: 

select 
    a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'') 
from 
    (select distinct COl1 from Tab) a 
Cross apply 
    (select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b 

方法2: 

select 
    a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44)) 
from 
    (select distinct COl1 from Tab) a 
cross apply 
    (select Col2=(select COl2 from Tab  where COl1=a.COl1 FOR XML AUTO, TYPE) 
                .query(' <Tab> 
                {for $i in /Tab[position() <last()]/@COl2 return concat(string($i),",")} 
                {concat("",string(/Tab[last()]/@COl2))} 
                </Tab>') 
                )b 

SQL05用CTE: 

;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab) 
,Ro