日期:2014-05-18 浏览次数:20685 次
declare @a nvarchar(50),@b nvarchar(50) set @a = ' 12:12 13:13 ',@b = ' 12:12 13:45 20:22 '
declare @a nvarchar(50),@b nvarchar(50) select @a = ' 12:12 13:13 ',@b = ' 12:12 13:45 20:22 ' SELECT REPLACE( (SELECT DISTINCT ','+ NULLIF(substring(a.col,b.number,charindex(' ',a.col+' ',b.number)-b.number),' ') FROM (SELECT LTRIM(@a+@b) AS col)a,master.dbo.spt_values AS b WHERE b.type='P' AND CHARINDEX(' ',' '+a.Col,b.number)=b.number FOR XML PATH ('')) ,',',' ') /* 12:12 13:13 13:45 20:22*/
------解决方案--------------------
declare @a nvarchar(50),@b nvarchar(50) set @a = '12:12 13:13 ' set @b = '12:12 13:45 20:22 ' set @b=right(@b,len(@b)-charindex(' ',@b)+1) set @a=@a+@b print @a ---结果 --12:12 13:13 13:45 20:22
------解决方案--------------------
declare @a nvarchar(50),@b nvarchar(50),@c nvarchar(50) set @a = ' 12:12 13:13 ' set @b = ' 12:12 13:45 20:22 ' set @a = replace(ltrim(rtrim(@a)),' ',',') set @b = replace(ltrim(rtrim(@b)),' ',',') select @c = isnull(@c+',','') + cnt from(select distinct substring(@a+','+@b,number,charindex(',',@a+','+@b+',',number)-number) cnt from master..spt_values where [type] = 'p' and number between 0 and len(@a+','+@b) and substring(','+@a+','+@b,number,1) = ',' )t select ' '+replace(@c,',',' ')+' ' /************* ---------------------------------------------------------------------------------------------------------------- 12:12 13:13 13:45 20:22 (1 行受影响)
------解决方案--------------------
/****************************************************************************************************************************************************** 合并分拆表数据 整理人:中国风(Roy) 日期:2008.06.06 ******************************************************************************************************************************************************/ --> --> (Roy)生成測試數據 if not object_id('Tab') is null drop table Tab Go Create table Tab([Col1] int,[Col2] nvarchar(1)) Insert Tab select 1,N'a' union all select 1,N'b' union all select 1,N'c' union all select 2,N'd' union all select 2,N'e' union all select 3,N'f' Go 合并表: SQL2000用函数: go if object_id('F_Str') is not null drop function F_Str go create function F_Str(@Col1 int) returns nvarchar(100) as begin declare @S nvarchar(100) select @S=isnull(@S+',','')+Col2 from Tab where Col1=@Col1 return @S end go Select distinct Col1,Col2=dbo.F_Str(Col1) from Tab go SQL2005用XML: 方法1: select a.Col1,Col2=stuff(b.Col2.value('/R[1]','nvarchar(max)'),1,1,'') from (select distinct COl1 from Tab) a Cross apply (select COl2=(select N','+Col2 from Tab where Col1=a.COl1 For XML PATH(''), ROOT('R'), TYPE))b 方法2: select a.Col1,COl2=replace(b.Col2.value('/Tab[1]','nvarchar(max)'),char(44)+char(32),char(44)) from (select distinct COl1 from Tab) a cross apply (select Col2=(select COl2 from Tab where COl1=a.COl1 FOR XML AUTO, TYPE) .query(' <Tab> {for $i in /Tab[position() <last()]/@COl2 return concat(string($i),",")} {concat("",string(/Tab[last()]/@COl2))} </Tab>') )b SQL05用CTE: ;with roy as(select Col1,Col2,row=row_number()over(partition by COl1 order by COl1) from Tab) ,Ro