日期:2014-05-18 浏览次数:20641 次
select * from A where binary_checksum(*) not in (select binary_checksum(*) from B)
------解决方案--------------------
select * from A
where not exists(select 1 from binary_checksum(*) from B where CHECKSUM(*) = CHECKSUM(a.*))
------解决方案--------------------
select * from A where not exists(select 1 from binary_checksum(*) from B where CHECKSUM(*) = CHECKSUM(a.*))
------解决方案--------------------