日期:2014-05-18  浏览次数:20579 次

我有一个小问题,到哪也不急~~(我着急了,刚才回答的朋友们我粗心把null加引号了,所以答案基本都不对)
SQL code

declare @test table
(
    id int identity primary key,
    name nvarchar(20),
    Logo nvarchar(20)
)
insert into @test values('aaa','aaa.jpg')
insert into @test values('aaa',null)
insert into @test values('bbb',null)
insert into @test values('ccc',null)
insert into @test values('ccc',null)
insert into @test values('ccc','ccc.jpg')
insert into @test values('bbb','bbb.jpg')
insert into @test values('ddd','ddd.jpg')




需要结果:
id name logo
1 aaa aaa.jpg
4 ccc null
5 bbb bbb.jpg
6 ddd ddd.jpg

解释下:就是说按照name分组排序,条件是如果有N条,那么取logo不为空的那条,如果只有一条,那么无论为空不为空都显示出来。
谢谢大家。

蛋疼,刚才null加引号了。郁闷

------解决方案--------------------
SQL code
declare @test table
(
    id int identity primary key,
    name nvarchar(20),
    Logo nvarchar(20)
)
insert into @test values('aaa','aaa.jpg')
insert into @test values('aaa',null)
insert into @test values('bbb',null)
insert into @test values('ccc',null)
insert into @test values('ccc',null)
insert into @test values('ccc','ccc.jpg')
insert into @test values('bbb','bbb.jpg')
insert into @test values('ddd','ddd.jpg')


select distinct t.* from @test a
cross apply(select top 1 * from @test where name=a.name order by Logo desc) t


/*
id          name                 Logo
----------- -------------------- --------------------
1           aaa                  aaa.jpg
6           ccc                  ccc.jpg
7           bbb                  bbb.jpg
8           ddd                  ddd.jpg

(4 行受影响)

------解决方案--------------------
SQL code

declare @test table
(
    id int identity primary key,
    name nvarchar(20),
    Logo nvarchar(20)
)
insert into @test values('aaa','aaa.jpg')
insert into @test values('aaa',null)
insert into @test values('bbb',null)
insert into @test values('ccc',null)
insert into @test values('ccc',null)
insert into @test values('ccc','ccc.jpg')
insert into @test values('bbb','bbb.jpg')
insert into @test values('ddd','ddd.jpg')
insert into @test values('eee',null)

select * from @test a where isnull(Logo,'')=
(select isnull(max(Logo),'') from @test where name=a.name)
/*
id          name                 Logo
----------- -------------------- --------------------
1           aaa                  aaa.jpg
6           ccc                  ccc.jpg
7           bbb                  bbb.jpg
8           ddd                  ddd.jpg
9           eee                  NULL
*/