日期:2014-05-18 浏览次数:20611 次
--'12/26/1999'为参数 A. 计算 ISO 周的标量值用户定义函数 下例中,用户定义函数 ISOweek 取日期参数并计算 ISO 周数。为了正确计算该函数,必须在调用该函数前唤醒调用 SET DATEFIRST 1。 CREATE FUNCTION ISOweek (@DATE datetime) RETURNS int AS BEGIN DECLARE @ISOweek int SET @ISOweek= DATEPART(wk,@DATE)+1 -DATEPART(wk,CAST(DATEPART(yy,@DATE) as CHAR(4))+'0104') --Special cases: Jan 1-3 may belong to the previous year IF (@ISOweek=0) SET @ISOweek=dbo.ISOweek(CAST(DATEPART(yy,@DATE)-1 AS CHAR(4))+'12'+ CAST(24+DATEPART(DAY,@DATE) AS CHAR(2)))+1 --Special case: Dec 29-31 may belong to the next year IF ((DATEPART(mm,@DATE)=12) AND ((DATEPART(dd,@DATE)-DATEPART(dw,@DATE))>= 28)) SET @ISOweek=1 RETURN(@ISOweek) END 下面是函数调用。注意 DATEFIRST 设置为 1。 SET DATEFIRST 1 SELECT master.dbo.ISOweek('12/26/1999') AS 'ISO Week' 下面是结果集。 ISO Week ---------------- 52