求一SQL语句：出现次数最多的前40个列出来
表名：aaa，只有一列整形int，列名id
现在有一些记录记录：
50
52
52
52
52
52
52
53
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53
53
53
53
53
53
53
53
53
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53
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53
56
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56
62
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62
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64
64
64
64
64
64
64
64
64
64
64
64
64
64
64
64
64
80
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81
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83
85
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86
86
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86
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101
101
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101
101
101
101
101
101
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106
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109
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110
110
110
110
110
110
110
110
110
113
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113
113
113
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114
...
求一SQL语句把出现次数最多的前40个列出来（重复的只列一个）？请教了

------解决方案--------------------
select top 40 id from aaa group by id order by count(*) desc
------解决方案--------------------
select top 40 id from aaa group by id order by count(id) desc
------解决方案--------------------

create table aaa
(
id varchar(10),
)
insert into aaa select '1 '
insert into aaa select '1 '
insert into aaa select '1 '
insert into aaa select '2 '
insert into aaa select '2 '
insert into aaa select '2 '
insert into aaa select '3 '
insert into aaa select '3 '
insert into aaa select '4 '

select top 40 id,count(id) num
from aaa
group by id
order by count(id) desc

drop table aaa
------解决方案--------------------
select top 40 * from (select id,count(*) as bb from aaa group by id)a order by bb desc
------解决方案--------------------
select top 40 id into #temp from aaa group by id order by count(id) desc
------解决方案--------------------
select top 40 id from aaa
group by id
order by count(*) desc