oracle 求某一列最大值,其他列的值
比如我有一个table a
ID Num
1 10
2 52
7 6
4 79
我现在想求出Num值最大的那一行的ID
上例中Num最大79,对应ID是4
oracle有没有简便的写法
------解决方案--------------------select ID from a where NUM =(select max(NUM) from a);
------解决方案--------------------with a as(
select 1 id,10 num from dual union all
select 2,52 from dual union all
select 7,6 from dual union all
select 4,79 from dual)
select ID from (
select a.*,rank() over(order by num desc) rk from a)
where rk = 1
------解决方案--------------------select b.id from a b where not exists(select 1 from a where num>b.num)
------解决方案--------------------select id from a where point = (select MAX(num) from a)