日期:2014-05-16 浏览次数:20964 次
create table MAIN ( ID VARCHAR2(6), NAME VARCHAR2(6) ) create table TEST1 ( ID VARCHAR2(6) , MONEY NUMBER, STATE VARCHAR2(8), RIQI VARCHAR2(10), XIAOZU VARCHAR2(6) ) create table TEST2 ( ID VARCHAR2(6), MONEY NUMBER, STATE VARCHAR2(8), RIQI VARCHAR2(10), XIAOZU VARCHAR2(6) ) insert into main (ID, NAME) values ('1', '小组1'); insert into main (ID, NAME) values ('2', '小组2'); insert into main (ID, NAME) values ('3', '小组3'); insert into test1 (ID, MONEY, STATE, RIQI, XIAOZU) values ('1', 100, '已完成', '2012-02-10', '1'); insert into test1 (ID, MONEY, STATE, RIQI, XIAOZU) values ('2', 300, '处理中', '2012-03-1', '1'); insert into test1 (ID, MONEY, STATE, RIQI, XIAOZU) values ('3', 150, '已完成', '2012-02-15', '2'); insert into test1 (ID, MONEY, STATE, RIQI, XIAOZU) values ('4', 80, '已完成', '2012-02-23', '2'); insert into test1 (ID, MONEY, STATE, RIQI, XIAOZU) values ('5', 30, '已完成', '2012-03-23', '1'); insert into test2 (ID, MONEY, STATE, RIQI, XIAOZU) values ('1', 200, '已完成', '2012-02-5', '1'); insert into test2 (ID, MONEY, STATE, RIQI, XIAOZU) values ('2', 50, '处理中', '2012-05-26', '2'); insert into test2 (ID, MONEY, STATE, RIQI, XIAOZU) values ('3', 60, '已完成', '2012-03-7', '3'); insert into test2 (ID, MONEY, STATE, RIQI, XIAOZU) values ('4', 20, '处理中', '2012-02-17', '1');
select t1.name 小组名称, substr(t2.riqi, 1, 7) 月份, count(decode(t2.state, '已完成', 1, '')) TEST1表已完成总条数, sum(decode(t2.state, '已完成', t2.money, 0)) TEST1表已完成总金额, count(decode(t2.state, '处理中', 1, '')) TEST1表处理中总条数, sum(decode(t2.state, '处理中', t2.money, 0)) TEST1表处理中总金额 from main t1,test1 t2 where t2.xiaozu = t1.id group by t1.name,substr(t2.riqi, 1, 7) order by t1.name,substr(t2.riqi, 1, 7)
--就是在原来sql的基础上,就一个子查询,同时把原来的排序问题也就解决了。 select 小组名称, 月份, sum(TEST1表已完成总条数), sum(TEST1表已完成总金额), sum(TEST1表处理中总条数), sum(TEST1表处理中总金额), sum(TEST2表已完成总条数), sum(TEST2表已完成总金额), sum(TEST2表处理中总条数), sum(TEST2表处理中总金额) from ( select t1.name 小组名称, substr(t2.riqi, 1, 7) 月份, count(decode(t2.state, '已完成', 1, '')) TEST1表已完成总条数, sum(decode(t2.state, '已完成', t2.money, 0)) TEST1表已完成总金额, count(decode(t2.state, '处理中', 1, '')) TEST1表处理中总条数, sum(decode(t2.state, '处理中', t2.money, 0)) TEST1表处理中总金额, 0 TEST2表已完成总条数, 0 TEST2表已完成总金额, 0 TEST2表处理中总条数, 0 TEST2表处理中总金额 from main t1,test1 t2 where t2.xiaozu = t1.id group by t1.name,substr(t2.riqi, 1, 7) union all select t1.name 小组名称, substr(t2.riqi, 1, 7) 月份, 0 TEST1表已完成总条数, 0 TEST1表已完成总金额, 0 TEST1表处理中总条数, 0 TEST1表处理中总金额, count(decode(t2.state, '已完成', 1, '')) TEST2表已完成总条数, sum(decode(t2.state, '已完成', t2.money, 0)) TEST2表已完成总金额, count(decode(t2.state, '处理中', 1, '')) TEST2表处理中总条数, sum(decode(t2.state, '处理中', t2.money, 0)) TEST2表处理中总金额 from main t1,test2 t2 where t2.xiaozu = t1.id group by t1.name,substr(t2.riqi, 1, 7) ) group by 小组名称, 月份 order by 小组名称, 月份