日期:2014-05-17  浏览次数:20987 次

如何将一个字符串转化成一个表?
字符串 1,0,100,5;2,100,500,20;3,500,1000,40;

转化成如下表
1 0 100 5
2 100 500 20
3 500 1000 40


------解决方案--------------------
知道字符串的固定格式吗?

如果格式固定的话,可以通过截取字符串来解决

用截取函数substring
------解决方案--------------------
SQL code
sys@TBWORA> with a as (select ';'||'1,0,100,5;2,100,500,20;3,500,1000,40;' as str1 from dual),
  2       b as (select substr(str1, instr(str1,';',1,level)+1,
  3                                 instr(str1,';',1,level+1)-instr(str1,';',1,level)-1) as str2
  4              from a connect by level <=length(a.str1)-length(replace(a.str1,';','')) ),
  5       c as (select str2,
  6                    substr(str2,1, instr(str2,',',1,1)-1) as str2_p1,
  7                    substr(str2,instr(str2,',',1,1)+1,instr(str2,',',1,2)-instr(str2,',',1,1)-1) as str2_p2,
  8                    substr(str2,instr(str2,',',1,2)+1,instr(str2,',',1,3)-instr(str2,',',1,2)-1) as str2_p3,
  9                    substr(str2,instr(str2,',',1,3)+1) as str2_p4
 10             from b )
 11  select c.str2, c.str2_p1, c.str2_p2, c.str2_p3, c.str2_p4 from c;

STR2                STR2_P1      STR2_P2      STR2_P3      STR2_P4
------------------- ------------ ------------ ------------ ------------
1,0,100,5           1            0            100          5
2,100,500,20        2            100          500          20
3,500,1000,40       3            500          1000         40

------解决方案--------------------
SQL code
with a as (select ';'||'1,0,100,5;2,100,500,20;3,500,1000,40;' as str1 from dual),
     b as (select substr(str1, instr(str1,';',1,level)+1,
                               instr(str1,';',1,level+1)-instr(str1,';',1,level)-1) as str2 
            from a connect by level <=length(a.str1)-length(replace(a.str1,';','')) )
select b.str2 from b;

STR2
------------------------
1,0,100,5
2,100,500,20
3,500,1000,40


-- 上一步是拆分分号(;),下一步是拆分逗号(,) (如果你每部分的逗号最多三个,即:最多四个字段,则可以这样写:)
with a as (select ';'||'1,0,100,5;2,100,500,20;3,500,1000,40;' as str1 from dual),
     b as (select substr(str1, instr(str1,';',1,level)+1,
                               instr(str1,';',1,level+1)-instr(str1,';',1,level)-1) as str2 
            from a connect by level <=length(a.str1)-length(replace(a.str1,';','')) ),
     c as (select str2, 
                  substr(str2,1, instr(str2,',',1,1)-1) as str2_p1,
                  substr(str2,instr(str2,',',1,1)+1,instr(str2,',',1,2)-instr(str2,',',1,1)-1) as str2_p2,
                  substr(str2,instr(str2,',',1,2)+1,instr(str2,',',1,3)-instr(str2,',',1,2)-1) as str2_p3,
                  substr(str2,instr(str2,',',1,3)+1) as str2_p4
           from b )
select c.str2, c.str2_p1, c.str2_p2, c.str2_p3, c.str2_p4 from c;

------解决方案--------------------
观望罗老湿。
------解决方案--------------------
SQL code

--多写了几行,写了个还算通用的
[SYS@orcl] SQL>WITH t AS(
  2    SELECT '1,0,100,5;2,100,500,20;3,500,1000,40;' col FROM dual
  3    UNION ALL
  4    SELECT '4,1,101,6;5,101,501,21;6,501,1001,41;' col FROM dual
  5    UNION ALL
  6    SELECT '7,2,102,7;8,102,502,22;9,502,1002,42;' col FROM dual
  7  )--上面是模拟数据,可以不用管
  8  SELECT REGEXP_SUBSTR(A, '[^, ]+', 1, 1) AS A1, --取第一个逗号前面所有字符(如果变换为其他字符自己改正)
  9         REGEXP_SUBSTR(A, '[^, ]+', 1, 2) AS A2, --取第二个逗号前面所有字符(如果变换为其他字符自己改正)
 10         REGEXP_SUBSTR(A, '[^, ]+', 1, 3) AS A3, --取第三个逗号前面所有字符(如果变换为其他字符自己改正)
 11         REGEXP_SUBSTR(A, '[^, ]+', 1, 4) AS A4  --取第四个逗号前面所有字符(如果变换为其他字符自己改正,如果还有字段继续按照规律添加【1,5】之类的)
 12    FROM (SELECT REGEXP_SUBSTR(RTRIM(COL, ';'), '[^; ]+', 1, L) AS A
 13            FROM T, (SELECT LEVEL L FROM DUAL CONNECT BY LEVEL <= 100) T1
 14           WHERE LENGTH(RTRIM(COL, ';')) -
 15                 LENGTH(REPLACE(RTRIM(COL, ';'), ';')) + 1 &g