日期:2014-05-17 浏览次数:20780 次
with t as( select 1 yg,'合格' pf,'33' dfr from dual union all select 2,'合格','22' from dual union all select 2,'合格','44' from dual union all select 2,'合格','33' from dual union all select 3,'合格','22' from dual union all select 4,'合格','11' from dual ) select yg 员工, sum(decode(pf, '合格', 1, 0)) 合格数, sum(decode(pf, '不合格', 1, 0)) 不合格数, sum(decode(dfr, '11', 1, 0)) 打分人11, sum(decode(dfr, '22', 1, 0)) 打分人22, sum(decode(dfr, '33', 1, 0)) 打分人33, sum(decode(dfr, '44', 1, 0)) 打分人44, sum(decode(dfr, '55', 1, 0)) 打分人55 from t group by yg 员工 合格数 不合格数 打分人11 打分人22 打分人33 打分人44 打分人55 ---------- ---------- ---------- ---------- ---------- ---------- ---------- ---------- 1 1 0 0 0 1 0 0 2 3 0 0 1 1 1 0 3 1 0 0 1 0 0 0 4 1 0 1 0 0 0 0
------解决方案--------------------
create table t1 (y_no number,score varchar2(10),d_no number); insert into t1 values (1,'合格',33); insert into t1 values (1,'不合格',55); insert into t1 values (2,'合格',22); insert into t1 values (2,'不合格',44); insert into t1 values (2,'合格',33); insert into t1 values (3,'不合格',22); insert into t1 values (4,'合格',11); select t1.y_no 员工, nvl(sum(decode(score,'合格',1,0)),0) 合格数, nvl(sum(decode(score,'不合格',1,0)),0) 不合格数, decode(sum(case when score='合格' and d_no=11 then 1 when score='不合格' and d_no=11 then 0 end),1,'合格',0,'不合格') 打分人11, decode(sum(case when score='合格' and d_no=22 then 1 when score='不合格' and d_no=22 then 0 end),1,'合格',0,'不合格') 打分人22, decode(sum(case when score='合格' and d_no=33 then 1 when score='不合格' and d_no=33 then 0 end),1,'合格',0,'不合格') 打分人33, decode(sum(case when score='合格' and d_no=44 then 1 when score='不合格' and d_no=44 then 0 end),1,'合格',0,'不合格') 打分人44, decode(sum(case when score='合格' and d_no=55 then 1 when score='不合格' and d_no=55 then 0 end),1,'合格',0,'不合格') 打分人55 from t1 group by t1.y_no order by t1.y_no 员工 合格数 不合格数 打分人11 打分人22 打分人33 打分人44 打分人55 -------------------------------------- 1 1 1 合格 不合格 2 2 1 合格 合格 不合格 3 0 1 不合格 4 1 0 合格