日期:2014-05-17 浏览次数:20810 次
SELECT a,b FROM ( SELECT decode(col,1,rn) a,lead(decode(col,0,rn))over(ORDER BY 1) b FROM ( SELECT rn, MOD(rn,2) col FROM (SELECT ROWNUM rn FROM dual CONNECT BY ROWNUM<7) ) ) WHERE a IS NOT NULL AND b IS NOT NULL --2列的情况: 1 2 3 4 5 6
------解决方案--------------------
--创建环境
create table tmpTable as
with tmp as (
select 1 as col1 from dual
union
select 2 from dual
union
select 3 from dual
union
select 4 from dual
union
select 5 from dual
union
select 6 from dual
)
select * from tmp;
--创建存储过程
CREATE OR REPLACE PROCEDURE TEST_COL_TO_ROW
(
colNum IN INT,
user_cursor out sys_refcursor
)
AS
V_SQL VARCHAR2(8000);
BEGIN
V_SQL := 'SELECT ';
FOR X IN 1..colNum LOOP
V_SQL := V_SQL || 'SUM(DECODE(mod(rownum-1,'||to_char(colNum)||'),'||to_char(x-1)||',col1,0)) COL'||to_char(x) || ',' ;
END LOOP;
V_SQL := RTRIM(V_SQL,',');
V_SQL := V_SQL || ' from tmpTable group by trunc((rownum-1)/'||to_char(colNum)||') order by trunc((rownum-1)/'||to_char(colNum)||')';
--DBMS_OUTPUT.PUT_LINE(V_SQL);
OPEN user_cursor FOR V_SQL;
--EXECUTE IMMEDIATE V_SQL;
END;
--SQLPLUS中执行
SQL> variable v_c refcursor;
SQL> exec TEST_COL_TO_ROW(2,:v_c);
PL/SQL 过程已成功完成。
SQL> print :v_c;
COL1 COL2
---------- ----------
1 2
3 4
5 6
SQL> variable v_c refcursor;
SQL> exec TEST_COL_TO_ROW(3,:v_c);
PL/SQL 过程已成功完成。
SQL> print :v_c;
COL1 COL2 COL3
---------- ---------- ----------
1 2 3
4 5 6
------解决方案--------------------
select wm_concat(a) from tablet group by ceil(a/n)
n自己确定