求oracle中最大值、最小值和平均值语句!
我的查询语句是这样的:
select S_sampled_date,SP_sampling_point,(sum(decode(R_name, '硫含量 ',R_value))) as value_lhl from u_sample where S_sampled_date between to_date( '2008-1-1 ', 'yyyy-mm-dd ') and to_date( '2008-5-5 ', 'yyyy-mm-dd ') and to_char(S_sampled_date, 'D ') -1 in (1,3,5) and S_sampling_point_id = 'LYD2_TQYY ' group by S_sampled_date,SP_sampling_point order by value_lhl desc
查询出结果是:
S_sampled_date SP_sampling_point value_lhl
2008-1-9 2#原油 0.2
2008-1-2 2#原油 0.18
2008-1-11 2#原油 0.16
2008-1-4 2#原油 0.13
2008-1-7 2#原油 0.06
我的意思是在这个基础上取得最大值,最小值和平均值,根据上面的查询结果应该分别为0.2、0.06、0.146,请问我怎么写oracle语句呢?谢谢帮忙!
------解决方案--------------------select SP_sampling_point,max(value_lhl),min(value_lhl),avg(value_lhl)
from
(select S_sampled_date,SP_sampling_point,(sum(decode(R_name, '硫含量 ',R_value))) as value_lhl from u_sample where S_sampled_date between to_date( '2008-1-1 ', 'yyyy-mm-dd ') and to_date( '2008-5-5 ', 'yyyy-mm-dd ') and to_char(S_sampled_date, 'D ') -1 in (1,3,5) and S_sampling_point_id = 'LYD2_TQYY ' group by S_sampled_date,SP_sampling_point order by value_lhl desc) a
group by SP_sampling_point
------解决方案--------------------楼上正解 建议楼主熟悉下Oracle的一些基本函数
------解决方案--------------------樓主應該是問一句再實現 "最大值,最小值和平均值 "的方法。