日期:2014-05-17 浏览次数:20691 次
select table_name, comments from user_tab_comments; SELECT table_name FROM User_All_Tables;
------解决方案--------------------
汇总各位的如下:
SELECT * FROM user_tab_comments; SELECT * FROM User_All_Tables; SELECT * FROM tab; select * from dba_objects where OBJECT_TYPE='TABLE'; select * from all_tables; SELECT * FROM user_tables ; SELECT * FROM user_objects ;
------解决方案--------------------
user_tables;