关于JOB的问题??
需实现这样一个功能,
JOB1实现每天0时0分调用PROC_1
JOB2实现每月0时0分调用PROC_2
???????

------解决方案--------------------
begin
sys.dbms_job.submit(job => :job,
what => 'PROC_1;',
next_date => to_date('12-07-2008', 'dd-mm-yyyy'),
interval => 'trunc(sysdate)+1');
commit;
end;

begin
sys.dbms_job.submit(job => :job,
what => 'PROC_2;',
next_date => to_date('12-07-2008', 'dd-mm-yyyy'),
interval => 'trunc(sysdate)+1');
commit;
end;
------解决方案--------------------
没什么特殊的地方吧
------解决方案--------------------
第二个的interval改为'TRUNC(LAST_DAY(SYSDATE ) + 1)'
------解决方案--------------------
begin 
sys.dbms_job.submit(job => :job, 
what => 'PROC_1;', 
next_date => sysdate, 
interval => 'trunc(sysdate)+1'); 
commit; 
end; 

begin 
sys.dbms_job.submit(job => :job, 
what => 'PROC_2;', 
next_date => sysdate,
interval => 'trunc(last_day(sysdate))+1'); 
commit; 
end;