字段
id   col1  col2
1     3     4
2     55    66
3     44    33

with t(id,col1,col2) as(
select 1,3,4 from dual
union all select 2,55,66 from dual
union all select 3,67,33 from dual
union all select 4,1,77 from dual
union all select 5,2,76 from dual
)
select * from t order by (case when col2>col1 then col2 else col1 end);

------解决方案--------------------
探讨

SQL code


select id,col1,col2
   from t
  order by greatest(col1,col2);
--最小用 least


------解决方案--------------------
select * from table order by (case when col2>col1 then col2 else col1 end);
试下这个。。

------解决方案--------------------
探讨

select * from table order by (case when col2>col1 then col2 else col1 end);
试下这个。。


------解决方案--------------------
探讨

SQL code


select id,col1,col2
   from t
  order by greatest(col1,col2);
--最小用 least


------解决方案--------------------
探讨

[code=SQL]
select id,col1,col2
  from t
 order by greatest(col1,col2);
--最小用 least
[code]


------解决方案--------------------
oracle里面 函数挺多的  要靠自己挖掘了 很多功能强大但是用到的比较少

------解决方案--------------------
with t(id,col1,col2) as(
select 1,3,4 from dual
union all select 2,55,66 from dual
union all select 3,67,33 from dual
union all select 4,1,77 from dual
union all select 5,2,76 from dual
)
select * from t order by (case when col2>col1 then col2 else col1 end);


------解决方案--------------------
探讨

SQL code


select id,col1,col2
   from t
  order by greatest(col1,col2);
--最小用 least