select *
  from (select distinct *
          from (select ctm.id_       ctmId,
                       ctm.name_     ctmName,
                       ctr.id_       ctrId,
                       ctr.name_     ctrName,
                       ctr.email_    ctrEmail,
                       ctr.mphone_   ctrMphone,
                       ctr.brithday_ ctrBrithday
                  from contacter_ ctr
                 inner join customer_ ctm
                    on ctr.fk_customer_ = ctm.id_
                 inner join user_ u
                    on ctm.fk_user_ = u.id_
                 inner join ctm_ctg_lk_ ctmCtg
                    on ctmCtg.fk_ctm_ = ctm.id_
                 inner join ctm_ctg_ cc
                    on ctmCtg.fk_ctm_ctg_ = cc.id_
                 where ctr.brithday_ like '%-04-12'
                   and u.id_ in ('5dfaf039298290ee0129d51355e5029e',
                 regexp_like(ctr.mphone_,
                                   '^((13[0-9])|(15[^4,\D])|(18[0,5-9]))\d{8}$')))
         order by ctmId asc)
 where rownum <=?

------解决方案--------------------
SQL code

select *
  from (select distinct *
          from (select ctm.id_       ctmId,
                       ctm.name_     ctmName,
                       ctr.id_       ctrId,
                       ctr.name_     ctrName,
                       ctr.email_    ctrEmail,
                       ctr.mphone_   ctrMphone,
                       ctr.brithday_ ctrBrithday
                  from contacter_ ctr
                 inner join customer_ ctm
                    on ctr.fk_customer_ = ctm.id_
                 inner join user_ u
                    on ctm.fk_user_ = u.id_
                 inner join ctm_ctg_lk_ ctmCtg
                    on ctmCtg.fk_ctm_ = ctm.id_
                 inner join ctm_ctg_ cc
                    on ctmCtg.fk_ctm_ctg_ = cc.id_
                 where ctr.brithday_ like '%-04-12'
                   and u.id_ in ('5dfaf039298290ee0129d51355e5029e',
                 regexp_like(ctr.mphone_,
                                   '^((13[0-9])|(15[^4,\D])|(18[0,5-9]))\d{8}$')))
         order by ctmId asc)
 where rownum <=？

------解决方案--------------------

SQL code

select *
  from (select distinct *
          from (select ctm.id_       ctmId,
                       ctm.name_     ctmName,
                       ctr.id_       ctrId,
                       ctr.name_     ctrName,
                       ctr.email_    ctrEmail,
                       ctr.mphone_   ctrMphone,
                       ctr.brithday_ ctrBrithday
                  from contacter_ ctr
                 inner join customer_ ctm on ctr.fk_customer_ = ctm.id_
                 inner join user_ u on ctm.fk_user_ = u.id_
                 inner join ctm_ctg_lk_ ctmCtg on ctmCtg.fk_ctm_ = ctm.id_
                 inner join ctm_ctg_ cc on ctmCtg.fk_ctm_ctg_ = cc.id_
                 where ctr.brithday_ like '%-04-12'
                   and u.id_ = '5dfaf039298290ee0129d51355e5029e' --这个直接用=号
                   and regexp_like(ctr.mphone_, --前面加个and关系符
                                   '^