select a.1, a.2 from a, b

------解决方案--------------------
去掉那段查询逻辑。

------解决方案--------------------
SQL code

---无视B
select a.id, b.name from a, b where a.id=b.id(+)
---无视A
select a.id, b.name from a, b where a.id(+)=b.id

------解决方案--------------------

s.infoid(+) = a.id

这个A表跟S表是什么关系？
如果是一对一或者多对一  就不会重复
如果是一对多或者多对多就会重复    不知道我理解的对不对


                select distinct a.*,u.*,d.*                 from PC12315_INFO_TD  a,
                      base_user_info   u,
                      PC_DEPARTMENT_TC d,
                      pc_distribute_td s
                where a.accRegId = u.id(+)
                  and a.regDepId = d.id(+)
                  and a.dealNo is null
                  and s.infoid(+) = a.id
                  and ((a.currentState = '2' and
                      (a.regDepId = :dep or a.currentDeptId = :dep)) or
                      (a.currentState in ('7', '0') and
                      a.currentDeptId = :dep and a.regDepId != :dep and
                      s.accDeptId = :dep))
                  and a.regTime >= to_date(:beginDate, 'yyyy-MM-dd')
                  and a.regTime <=
                      to_date(:endDate, 'yyyy-MM-dd hh24:mi:ss')
                order by a.regTime desc

这样应该就能过滤掉因为S表 而重复的记录