关于Select和Insert into的组合

SQL code

SELECT TD.CUSTOMER_NO,TD.CARE_MONTH
FROM table
WHERE
CUSTOMER_NO = '1' AND CARE_MONTH = '20120821'

SQL code

INSERT INTO
table(CUSTOMER_NO,CARE_MONTH,REGISTER,REGIST_TIME,UPDATER,UPDATE_TIME)
VALUES('1','20120821')

可否用一个SQL文
实现SELECT查不出来数据的话
就把这条数据查到数据库里

------解决方案--------------------
insert into table1(CUSTOMER_NO,CARE_MONTH) --列的数量一定要和插入的值个数一样
(select * 
 from (select '1' id,'20120821' name ) a --这个是MSSQL中的写法
 where not exists (SELECT 1 
FROM table1 
WHERE CUSTOMER_NO = '1' 
AND CARE_MONTH = '20120821')
)

以上在MSSQL中测试是没问题的


 

------解决方案--------------------

探讨

SQL code


SELECT TD.CUSTOMER_NO,TD.CARE_MONTH
FROM table
WHERE
CUSTOMER_NO = '1' AND CARE_MONTH = '20120821'




SQL code


INSERT INTO
table(CUSTOMER_NO,CARE_MONTH,REGISTER,REGIST_TIM……

------解决方案--------------------
最好使用merge吧，效率比较高。
------解决方案--------------------
是Oracle数据库还是mysql数据库呢？
------解决方案--------------------
merge into security_clutter a 
using (select '90001' ls_code,'PWD' act_code ,'test' act_name 
from dual ) b 
on (a.act_code = b.act_code) 
when matched then 
update set a.act_name = b.act_name 
when not matched then 
insert values (b.ls_code, b.act_code, b.act_name, '', '')
------解决方案--------------------
楼上的when matched的应该可以跳过，直接when not matched...
------解决方案--------------------
merge 可以解决！