日期:2011-05-03 浏览次数:20483 次
<?php
if(!$_GET["screenX"]) {
echo '
<script>
location = location.href+"?screenX="+screen.width+"&screenY="+screen.height;
</script>
';
exit;
}
$screenX = $_GET["screenX"];
$screenY = $_GET["screenY"];
?>
以下是其他内容