ajax 取值

 

 $.ajax({

   type: "post",   

   url: "ddd.php",   

   data: {"inserted":[{"productionName":"空压机","product":"科兴","productionType":"KX-11D","fenjieselect":"分解","proctionNO":"02"},{"productionName":"空压机","product":"科兴","productionType":"KX-12D","fenjieselect":"分解","proctionNO":"03"}],"updated":[],"deleted":[]},   

   datatype: "text",

   success:function(data){

    alert (data);



 } 



})  

我在后台的PHP里如何取到inserted ,updated ,deleted 的值啊？
------解决方案--------------------
你不是写了POST接收吗？ 在ddd.php 里面print_r($_POST)
------解决方案--------------------

<?php

if($_POST) {

  print_r($_POST);

  exit;

}

?>

<script src='http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js'></script>

<script>

$(function() {

  $.ajax({

    type: "post",   

//   url: "ddd.php",   

    data: {"inserted":[{"productionName":"空压机","product":"科兴","productionType":"KX-11D","fenjieselect":"分解","proctionNO":"02"},{"productionName":"空压机","product":"科兴","productionType":"KX-12D","fenjieselect":"分解","proctionNO":"03"}],"updated":[],"deleted":[]},   

    datatype: "text",

    success:function(data){

      alert (data);

    }

  });

});

</script>