真诚求一个自定义，谢谢


当输入
Monday/Tuesday/Wednesday/Thursday/Friday/Saturday/Sunday
输出
1,2,3,4,5,6,7

为了便于扩展，最好使用数组。

------解决方案--------------------

function foo($s) {

  $dict = array_flip(explode(',', '/,monday,tuesday,wednesday,thursday,friday,saturday,sunday'));

  $dict['/'] = ',';

  return strtr(strtolower($s), $dict);

}



echo foo('Monday/Tuesday/Wednesday/Thursday/Friday/Saturday/Sunday');

1,2,3,4,5,6,7

------解决方案--------------------
空格和'/'均作处理

function foo($s) {

	$array=array('monday'=>1,

							'tuesday'=>2,

							'wednesday'=>3,

							'thursday'=>4,

							'friday'=>5,

							'saturday'=>6,

							'sunday'=>7,

							'/'=>',',' '=>',');

  return strtr(strtolower($s), $array);

} 

echo foo('Monday Tuesday Wednesday/Thursday/Friday/Saturday/Sunday');

------解决方案--------------------

function foo($s) {

    $array= array('monday'   => 1,

                 'tuesday'  => 2,

                 'wednesday'=> 3,

                 'thursday' => 4,

                 'friday'   => 5,

                 'saturday' => 6,

                 'sunday'   => 7,

                );



    $sa = preg_split('/\W/',strtolower($s));

    $arr = array();

    foreach ($sa as $v) {

        if(is_numeric($v)) {

            $t = array_values($array);

            $arr[] = $t[$v-1];

        }

        else if (isset($array[$v])) {

            $arr[] = $array[$v];

        }

        else {

            foreach ($array as $k1 => $v1 )  {

                if ( substr($k1, 0, 4) == $v ) {

                    $arr[] = $v1; break;

  &nb