日期:2014-05-17 浏览次数:20542 次
?
今天重新吧 小型twitter系統的源碼 認真研究了一邊 算是熟悉php把?
爲今後一個月的畢業設計做打算
?
下載
http://dl.vmall.com/c0nkwafdqz
?
index
?
<?php session_start (); include_once ('header.php'); include_once ('functions.php'); $_SESSION ['userid'] = 1;//设置session真正情况是在登录的时候设置 ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <title>Microblogging Application</title> </head> <p> <a href='users.php'>see list of users</a> </p> <?php if (isset ( $_SESSION ['message'] )) {//如果session中设置了message就显示出来.然后释放 echo "<b>" . $_SESSION ['message'] . "</b>"; unset ( $_SESSION ['message'] ); } ?> <form method='post' action='add.php'> <p>Your status:</p> <textarea name='body' rows='5' cols='40' wrap=VIRTUAL></textarea> <p> <input type='submit' value='submit' /> </p> <?php $users = show_users($_SESSION['userid']);//显示用户follow的用戶 if (count($users)){ $myusers = array_keys($users);//返回數組中所有的key }else{ $myusers = array(); } $myusers[] = $_SESSION['userid'];//應該在myusers數據末尾添加用戶自己 $posts = show_posts($myusers,5);//顯示用戶follow用戶的五條post if (count ( $posts )) { ?> <table border='1' cellspacing='0' cellpadding='5' width='500'> <?php foreach ( $posts as $key => $list ) { echo "<tr valign='top'>\n"; echo "<td>" . $list ['userid'] . "</td>\n"; echo "<td>" . $list ['body'] . "<br/>\n"; echo "<small>" . $list ['stamp'] . "</small></td>\n"; echo "</tr>\n"; } ?> </table> <?php } else { ?> <p> <b>You haven't posted anything yet!</b> </p> <?php } ?> <h2>Users you're following</h2> <?php $users = show_users ( $_SESSION ['userid'] ); if (count ( $users )) { ?> <ul> <?php foreach ( $users as $key => $value ) { echo "<li>" . $value . "</li>\n"; } ?> </ul> <?php } else { ?> <p> <b>You're not following anyone yet!</b> </p> <?php } ?> </form> </body> </html>
headers
?
?
<?php $SERVER = 'localhost:3306'; $USER = 'root'; $PASS = 'root'; $DATABASE = 'tweet'; if (! ($mylink = mysql_connect ( $SERVER, $USER, $PASS ))) { echo "<h3>Sorry, could not connect to database.</h3><br/> Please contact your system's admin for more help\n"; exit (); } mysql_select_db ( $DATABASE ); ?>
users
<?php session_start (); include_once ("header.php"); include_once ("functions.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-