日期:2014-05-17 浏览次数:20479 次
$path = 'E:/Zl/资料-1/资料库/3005 奥迪A6L新型C6原厂资料'; function get_filetree($path){ $tree = array(); foreach(glob($path."/{*.pdf,*.doc,*.ppt}", GLOB_BRACE) as $single){ if(is_dir($single)){ $tree = array_merge($tree,get_filetree($single)); } else{ $tree[] = $single; } } return $tree; } print_r(get_filetree($path));
function get_filetree($path){ $tree = array(); foreach(glob($path."/*.{pdf,doc,ppt}", GLOB_BRACE) as $single) { if(is_file($single)) $tree[] = $single; } foreach(glob($path."/*", GLOB_ONLYDIR ) as $single) { $tree = array_merge($tree,get_filetree($single)); } return $tree; }
------解决方案--------------------
你#6的写法也是可以的,但用错了目标
if(glob($path."*/*.{pdf,doc,ppt}", GLOB_BRACE)){
应为
if(glob($single."{pdf,doc,ppt}", GLOB_BRACE)){
目的是判断 $single 的后缀是否符合要求
我#4的代码:
//取得所有符合条件的文件名
foreach(glob($path."/*.{pdf,doc,ppt}", GLOB_BRACE) as $single) {
if(is_file($single)) $tree[] = $single;
}
//遍历所有子目录
foreach(glob($path."/*", GLOB_ONLYDIR ) as $single) {
$tree = array_merge($tree,get_filetree($single));
}