日期:2014-05-17 浏览次数:20425 次
$row = 1; $handle = fopen("test.csv","r"); while ($data = fgetcsv($handle, 1000, ",")) { $num = count($data); echo "<p> $num fields in line $row: <br>\n"; $row++; for ($c=0; $c < $num; $c++) { echo $data[$c] . "<br>\n"; } } fclose($handle); #我用上面的代码获取 #date #2011-4-21 #的数据能正常获取 #你的问题怎么解决的?