日期:2014-05-17 浏览次数:20576 次
<html> <head> <meta http-equiv="Content-Type" content="text/html" ;charset="charset"/> <title>handle_posting</title> <head> <body> <?php $first_name = $_POST['first_name']; $last_name = $_POST['last_name']; $email_address = $_POST['email_address']; $sex = $_POST['sex']; $posting = nl2br($_POST['posting']); $name = $first_name . ' ' . $last_name; echo <<<html "<div>Thank you,$name for your posting: <p>$posting</p> <p>our team will send the lastest meassage to $email_address.</p> </div> html; $name = urlencode($name);//使用urlencode进行链接 $email_address = urlencode($_POST['email_address']); echo "<p>Click<a href='hand_posting.php?name=$name&email_address=$email_address'>here</a>to continue.</p>"; ?> </body> </html>
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</p>
</div>" 加个分号 笨蛋!
</p>
</div>";
另外请用echo 输出
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出现Parse error: syntax error, unexpected '$name' (T_VARIABLE) in C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\handle_posting.php on line 18错误
这种错误几乎是:不是哪里少了个分号,就是哪里少了个引号。
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少分号