日期:2014-05-17  浏览次数:20517 次

MYSQL语句问题?
SQL code
UPDATE 
(
SELECT  WorkID,
WK.PpjID,
WD.CheckupPoint,
WD.AdjustPoint,
WD.FactPoint,
 WE.IsSpecial,
 WK.WorkType,
 WK.WorkStatus 
  FROM `Work` WK  LEFT JOIN WorkDesign WD ON WK.WorkID=WD.Work_id
LEFT JOIN WorkEditionDot WE ON WE.EditionDotID=WE.EditionDotID WHERE `WK`.WorkID IN
(SELECT `W`.WorkID   FROM `Work` W WHERE  W.PpjID=18035 AND (`W`.WorkStatus='已出稿' OR `W`.WorkStatus='已定稿')))   
 SET  WD.CheckupPoint=WD.AdjustPoint+WD.FactPoint WHERE  WK.PpjID=18035
报错;Every derived table must have its own alias该如何解决(别名问题)?

------解决方案--------------------
Every derived table must have its own alias
每一个派生表必须有自己的别名



UPDATE 
(
SELECT WorkID,
WK.PpjID,
WD.CheckupPoint,
WD.AdjustPoint,
WD.FactPoint,
WE.IsSpecial,
WK.WorkType,
WK.WorkStatus
FROM `Work` WK LEFT JOIN WorkDesign WD ON WK.WorkID=WD.Work_id
LEFT JOIN WorkEditionDot WE ON WE.EditionDotID=WE.EditionDotID WHERE `WK`.WorkID IN
(SELECT `W`.WorkID FROM `Work` W WHERE W.PpjID=18035 AND (`W`.WorkStatus='已出稿' OR `W`.WorkStatus='已定稿')))
SET WD.CheckupPoint=WD.AdjustPoint+WD.FactPoint WHERE WK.PpjID=18035
红色的部分就是一个派生表,需要有别名
被修改的是查询结果,你这样能修改成功吗?