PHP 如何轮循
我是想求能满足多少个订单？为什么我这样不行？？

$order_id = mysql_query("select order_id from myr_order where '".strtotime('-'.$date.' day')."' <= add_time and add_time <= '".mktime()."'");
while($t_id = mysql_fetch_array($order_id,MYSQL_ASSOC)){
$is_in =1;
$num = 0;
$que = mysql_query("select goods_sn,order_id from myr_order_goods where order_id = '".$t_id['order_id']."'");
while($gs = mysql_fetch_object($que)){
if(in_array($gs->goods_sn,$sn) && $is_in==1){
$is_in = 1;
}elseif(in_array($gs->goods_sn,$sn) && $is_in==0){
$is_in = 0;
break;
}
}
if($is_in == 1){
$num = $num + 1;
}elseif($is_in == 0){
continue;
}
}
  echo $num;

------解决方案--------------------

PHP code

$sql = "select order_id from myr_order where '".strtotime('-'.$date.' day')."' <= add_time and add_time <= '".mktime()."'";
$order_id = mysql_query($sql);
$num = 0;// 放到外面来试一试
while($t_id = mysql_fetch_array($order_id,MYSQL_ASSOC)){
    $is_in =1;
    $que = mysql_query("select goods_sn,order_id from myr_order_goods where order_id = '".$t_id['order_id']."'");

    $gs = mysql_fetch_object($que);
    if(in_array($gs->goods_sn,$sn) && $is_in){
        $is_in = 1;
    }elseif(in_array($gs->goods_sn,$sn) && !$is_in){
        $is_in = 0;
        break;
    }

    if($is_in){
        $num = $num + 1;
    }elseif(!$is_i){
        continue;
    }
}
  echo $num;