方法一
select? a.*? ,
REGEXP_SUBSTR(a.rolecode ,'[^,]+',1,l) AS rolecode
from p_user a,(SELECT LEVEL l FROM DUAL CONNECT BY LEVEL<=100) b
WHERE l <=LENGTH(a.rolecode) - LENGTH(REPLACE(rolecode,','))+1

?

?

?

使用函数REGEXP_SUBSTR拆分字符串：

5个参数

第一个是输入的字符串

第二个是正则表达式

第三个是标识从第几个字符开始正则表达式匹配。（默认为1）

第四个是标识第几个匹配组。（默认为1）

第五个是是取值范围：

i：大小写不敏感；

c：大小写敏感；

n：点号 . 不匹配换行符号；

m：多行模式；

x：扩展模式，忽略正则表达式中的空白字符。

SELECT a.*,REGEXP_SUBSTR(servicereqid ,'[^;]+',1,l) AS servicereq
? FROM sum_portal_satisfaction a,(SELECT LEVEL l FROM DUAL CONNECT BY LEVEL<=100) b
WHERE l <=LENGTH(servicereqid) - LENGTH(REPLACE(servicereqid,';'))+1
ORDER BY 1,2;

----SELECT LEVEL l FROM DUAL CONNECT BY LEVEL<=100; 生成1到100的数据行。
----l <=LENGTH(servicereqid) - LENGTH(REPLACE(servicereqid,';'))+1，注意此处是‘L’并非‘1’，上面的REGEXP_SUBSTR的第四个参数也一样。


---下面为拆分字符串，再进行的行转列
create or replace view v_sum_portal_satisfaction_sr as
select
survey_type,
survey_time,
center_code,
center_name,
city_id,
city_name,
REGEXP_SUBSTR(servicereqid ,'[^;]+',1,l) AS servicereqid,
REGEXP_SUBSTR(servicereqname ,'[^;]+',1,l) AS servicereqname,
sum(decode(survey_value,0, sur_times,null)) giveup_times,--调查值 -1:未处理 0:用户放弃 1:很满意 2.满意 3.对csr不满意 4.对其它不满意
sum(decode(survey_value,1, sur_times,null))vsatis_times,
sum(decode(survey_value,2, sur_times,null))satis_times,
sum(decode(survey_value,3, sur_times,null))ncsr_times,
sum(decode(survey_value,4, sur_times,null))nelse_times,
sum(sur_times) sur_times
? FROM sum_portal_satisfaction a,(SELECT LEVEL l FROM DUAL CONNECT BY LEVEL<=100) b
WHERE l <=LENGTH(servicereqid) - LENGTH(REPLACE(servicereqid,';'))+1
group by
subslevelid,
center_code,
center_name,
city_id,
city_name,
survey_type,
survey_time,
servicereqid,
servicereqname,l

?

?

?

?

?

方法二:

?
create table? testTable (
?????? id? nvarchar2(200) primary key not null ,
?????? content? nvarchar2(200) not null
)

insert into? testTable values ('4','馆内idx_10馆外idx_11总体idx_12');


select *? from table ( CAST (fn_split(('馆内idx_1$馆外idx_2$总体idx_3$') ,'$') as ty_str_split? )? )

?
?
?
??



select * from testtable b left join? table (fn_split((content), '$')?? ) a?? on 1=1;

--实现split函数
CREATE OR REPLACE TYPE ty_str_split IS TABLE OF VARCHAR2 (4000);

CREATE OR REPLACE FUNCTION fn_split (p_str IN VARCHAR2, p_delimiter IN VARCHAR2)
??? RETURN ty_str_split
IS
??? j INT := 0;
??? i INT := 1;
??? len INT := 0;
??? len1 INT := 0;
??? str VARCHAR2 (4000);
??? str_split ty_str_split := ty_str_split ();
BEGIN
??? len := LENGTH (p_str);
??? len1 := LENGTH (p_delimiter);

??? WHILE j < len
??? LOOP
??????? j := INSTR (p_str, p_delimiter, i);

??????? IF j = 0
??????? THEN
??????????? j := len;
??????????? str := SUBSTR (p_str, i);
??????????? str_split.EXTEND;
??????????? str_split (str_split.COUNT) := str;

??????????? IF i >= len
??????????? THEN
??????????????? EXIT;
??????????? END IF;
??????? ELSE
??????????? str := SUBSTR (p_str, i, j - i);
??????????? i := j + len1;
??????????? str_split.EXTEND;
??????????? str_split (str_split.COUNT) := str;
??????? END IF;
??? END LOOP;

??? RETURN str_split;
END fn_split;




DECLARE
??? CURSOR c
??? IS
select *? from table ( CAST (fn_split(('馆内idx_1$馆外idx_2$总体idx_3$') ,'$') as ty_str_split? )? );

??? r c%ROWTYPE;
BEGIN
??? OPEN c;

??? LOOP
??????? FETCH c INTO r;
??????? EXIT WHEN c%NOTFOUND;
??????? DBMS_OUTPUT.put_line (r.column_value);
??? END LOOP;

??? CLOSE c;